String in matrix for loop
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I have created the below for loop. The txt files are all composed by 16 elements, the first 8 are string and the seconde 8 are number and are separated by comma. At the moment I created a matrix with only the last 8 value. Is it possible also to create a matrix (no structure, no array) with also the first 8 string?
fileList = dir( '*.txt' );
for i = 1 : numel(fileList)
nameFile{i} = fileList(i,1).name;
NAME = char(nameFile(i) );
fid = fopen( NAME );
val = textscan( fid, '%s', 'delimiter', ',' );
fclose( fid );
if val{1,1}{5,1} == 'LIMA' | val{1,1}{6,1} == 'VOCI'
% for jj = 1 : 7
% VAL (i,jj)= char(val{1,1}{jj,1});
% end
for j = 8 : size( val{1,1},1 )
A(i, j) = str2num( val{1,1}{j,1} );
end
end
end
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Réponses (1)
Daniel Shub
le 25 Oct 2011
It really depends on what data type you are willing to allow. You say no structure and no array. MATLAB only deals with arrays; scalars are arrays with a length of 1. It seems like you also do not want cell arrays, since your data from textscan is a cell array.
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