# Replace table elements in more than one row

23 vues (au cours des 30 derniers jours)
Davindra Usov le 22 Mar 2023
Commenté : Davindra Usov le 23 Mar 2023
Hi,
I have outputted a vector (V) which contains the row indices of elements in a table (T) that contain the string 'rpm'.
T has 3 columns and I initially set all of the elements in column 3 to zero. I now wish to replace all elements in column 3 that have these row indices (so only row 3 and row 7) with a value of 6. I have tried doing this but it doesn't work:
V = [3;7]; % row indices
for i = 1:numel(V)
T(V(i), 3) = repmat(6, numel(V), 1);
end
I get an error saying To assign to or create a variable in a table, the number of rows must match the height of the
table.
Thank you
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VBBV le 23 Mar 2023
T = table(zeros(7,1),zeros(7,1),zeros(7,1),zeros(7,1)) % your table
T = 7×4 table
Var1 Var2 Var3 Var4 ____ ____ ____ ____ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
V = [3;7]; % row indices
T(V, 3) = [repmat({6},numel(V),1)] % put the element in cell array when assigning
T = 7×4 table
Var1 Var2 Var3 Var4 ____ ____ ____ ____ 0 0 0 0 0 0 0 0 0 0 6 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 6 0

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### Réponse acceptée

Cameron le 22 Mar 2023
You should look into how MATLAB does its indexing. You don't have to loop through the array to change a value. Just do it like this:
T = zeros(10,3); %i just picked 10 rows of data
indx = [3,7];
T(indx,3) = 6
T = 10×3
0 0 0 0 0 0 0 0 6 0 0 0 0 0 0 0 0 0 0 0 6 0 0 0 0 0 0 0 0 0
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Davindra Usov le 23 Mar 2023
thank you very much. This works perfectly. The others do as well, however I can only accept one answer

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### Plus de réponses (1)

Cris LaPierre le 22 Mar 2023
Modifié(e) : Cris LaPierre le 22 Mar 2023
You can, but the code you wrote is trying to replace a single element with a vector, hence the error message.
When you are trying to replace each element with the same value, you do not need to use repmat. Perhaps you are trying to do this?
tb = table(zeros(4,1))
tb = 4×1 table
Var1 ____ 0 0 0 0
tb.Var1([1 3]) = 6
tb = 4×1 table
Var1 ____ 6 0 6 0
% you could also use repmat if you want
tb.Var1([2 4]) = repmat(10,2,1)
tb = 4×1 table
Var1 ____ 6 10 6 10
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