Plotting Level Curves after function
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how do i plot level curves in matlab
such as c = 0, 0.5, 1, ..., 3.
i have already computed the code for the function
f (x, y) = (x2 + 3y2)e1−x2 −y2
over the domain −1 ≤ x ≤ 1, −1 ≤ y ≤ 1.
Réponses (1)
Star Strider
le 24 Mar 2023
0 votes
5 commentaires
Torsten
le 24 Mar 2023
"fimplicit" might also be an option.
@Torsten — I considered that, however that could require at least one explicit loop, where contour could do all the ‘c’ values using the LevelList argument. I would have simulated it here, except that I have no idea whether ‘e’ is a variable or the exponential function exp.
Assuming ‘e’ because of that ambiguity, one approach could be —
syms x y
f(x,y) = (x^2 + 3*y^2)*exp(1-x^2-y^2);
figure
fcontour(f, [-1 1 -1 1], 'LevelList',[0:0.5:3], 'Fill','on')
colormap(turbo)
colorbar
axis('equal')
.
lateef
le 25 Mar 2023
lateef
le 25 Mar 2023
If you want to use a function handle, my code changes to:
f = @(x,y) (x.^2 + 3*y.^2).*exp(1-x.^2-y.^2);
figure
fcontour(f, [-1 1 -1 1], 'LevelList',[0:0.5:3], 'Fill','on')
colormap(turbo)
colorbar
axis('equal')
That is the only change necessary. The 'Fill','on' is optional.
Your code would work with contour or contourf, although not with fcontour, since fcontour creates its own matrices and does not take them as arguments.
.
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