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what test to use on z-scores

13 vues (au cours des 30 derniers jours)
Joanne Hall
Joanne Hall le 25 Mar 2023
Commenté : Star Strider le 26 Mar 2023
Dear matlab,
I have z-scores of 2 groups. I want to compare them.
What test in matlab should I use for relative comparison using just the z scores?
Thanks in advance for any guidance!
Joanne
  4 commentaires
Star Strider
Star Strider le 26 Mar 2023
@Joanne Hall — As I illustrated in my Answer, unless you can reconstitute the original data from the respective means and standard deviations, there is nothing you can do to compare the two groups. Standardizing them erases any differences the two groups may once have had. However if you have the original means and standard deviations from each group, and if they are normally distributed, those are all you need to use to compare them.
Again, if you no longer have the means and standard deviations, you have my sympaties.
Joanne Hall
Joanne Hall le 26 Mar 2023
Thanks Star, see answr below

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Réponse acceptée

Star Strider
Star Strider le 25 Mar 2023
Since the zscore is simply a standardised method of expressing data, and if the mean values and standard deviation (std) values of each group are known, it is possible to map back to the original data and then do a valid comparison. However, if that information is not available and so it is not possible to cannot back-calculate to the original data, then your ability to discriminate the two gropus is likely lost, and no test will produce a valid comparison.
An example using random original and standardised data and the Wilcoxon ranksum test (assuming that the two groups are not paired) illustrates the issue —
x = randn(25,1);
y = randn(25,1)*3+5;
zx = zscore(x);
zy = zscore(y);
[p1,h1,stats1] = ranksum(x,y) % Original Data Are Significantly Different
p1 = 1.3090e-07
h1 = logical
1
stats1 = struct with fields:
zval: -5.2776 ranksum: 365
[p2,h2,stats2] = ranksum(zx,zy) % Standardised Scores OF The Original Data Are Not Significantly Different
p2 = 0.8009
h2 = logical
0
stats2 = struct with fields:
zval: -0.2522 ranksum: 624
So while the original data in this example are significantly different (the ranksum test assumes that both groups have the same underlying distribution, although the distribution itself is irrelevant), the standardised scores of the same data are not.
It is not worth the effort to compare the standardised scores, since any differences between the two groups that might have originally existed are lost in the standardisation process.
You have my sympathies.
.
  4 commentaires
Joanne Hall
Joanne Hall le 26 Mar 2023
thanks star!
Star Strider
Star Strider le 26 Mar 2023
As always, my pleasure!

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