How to integrate from 0 to infinity with x and 1 varying parameter?

2 vues (au cours des 30 derniers jours)
Sanzhar Kaidarov
Sanzhar Kaidarov le 9 Avr 2023
Hey, I need to simualte and plot the following function, but can't seem to figure it out. I tried implementin it and code is down below. On my first iteration(sadly, not saved) it launched and seemed to integrate, but the process was stuck, and I assume matlab was struggling with integration till infinity. Now it just not launching. Could you help with error that I have now and further show how can i implement this formula?
(a,b,d,p are generic numbers, I just want the code to run)
Thank you in advance, guys!
clear;
clc;
syms x;
u0 = 4*pi*10^-7;
L1 = 0.88e-6;
L2 = 0.88e-6;
a = 50*10^-3;
b = 50*10^-3;
d = 20*10^-3;
%p = 0:0.1*10^-2:0.5;
p = 0;
eq1 = besselj(1, x*sqrt(a/b));
eq2 = besselj(1, x*sqrt(b/a));
eq3 = besselj(0, x*p/sqrt(a*b));
eq4 = (exp(-x*d/sqrt(a*b)));
eq5 = pi*u0*sqrt(a*b);
eqf = eq1*eq2*eq3*eq4;
M = eq5*integral(eqf, 0, inf);

Réponses (1)

Walter Roberson
Walter Roberson le 9 Avr 2023
Déplacé(e) : Walter Roberson le 9 Avr 2023
syms x;
Pi = sym(pi);
u0 = 4*Pi*10^-7;
L1 = sym(88)*sym(10)^(-8);
L2 = sym(88)*sym(10)^(-8);
a = sym(50)*sym(10)^-3;
b = sym(50)*sym(10)^-3;
d = sym(20)*sym(10)^-3;
%p = 0:0.1*10^-2:0.5;
p = 0;
eq1 = besselj(1, x*sqrt(a/b));
eq2 = besselj(1, x*sqrt(b/a));
eq3 = besselj(0, x*p/sqrt(a*b));
eq4 = (exp(-x*d/sqrt(a*b)));
eq5 = Pi*u0*sqrt(a*b);
eqf = eq1*eq2*eq3*eq4
eqf = 
M = eq5*int(eqf, x, 0, inf)
M = 
vpa(M, 16)
ans = 
0.00000006753694369741884

Catégories

En savoir plus sur Mathematics dans Help Center et File Exchange

Produits


Version

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by