Seventh order differential equation
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    Francesco Marchione
 le 13 Avr 2023
  
    
    
    
    
    Modifié(e) : Torsten
      
      
 le 21 Avr 2023
            Hello,
I would like to solve this system of differential equations in Matlab (and in the end I would like to plot tau and sigma for -l and +l x values):

with these BCs:

where P, h_i, G_i, h_i are numbers (which I would like to define in the code).
Here I started with this:
% y''''''' - a*y'''''' + b*y''' - c*y' = 0
syms s x y(x) Y 
Dy = diff(y);
D2y = diff(y,2);
D3y = diff(y,3);
D4y = diff(y,4);
D5y = diff(y,5);
D6y = diff(y,6);
D7y = diff(y,7);
a==10
b==60
c==40
Eqn = D7y - a*D5y + b*D3y -c*Dy == 0;
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Réponse acceptée
  Torsten
      
      
 le 14 Avr 2023
        
      Modifié(e) : Torsten
      
      
 le 15 Avr 2023
  
      % Set model parameters
l = 1;
P = 1;
Ga = 1;
Eatilde = 1;
ha = 1;
E1tilde = 1;
h1 = 1;
E2tilde = 1;
h2 = 1;
xmesh = linspace(-l,l,100);
solinit = bvpinit(xmesh, [1 1 1 1 1 1 1 0 0 0]);
sol = bvp4c(@(x,y)bvpfcn(x,y,l,P,Ga,Eatilde,ha,E1tilde,h1,E2tilde,h2), @(ya,yb)bcfcn(ya,yb,l,P,Ga,Eatilde,ha,E1tilde,h1,E2tilde,h2),solinit);
x = sol.x;
tau = sol.y(1,:);
sigma = ((4/(E1tilde*h1)+2/(E2tilde*h2))*sol.y(2,:)- ha/Ga*sol.y(4,:))/(6/(E1tilde*h1^2));
figure(1)
plot(x,tau)
figure(2)
plot(x,sigma)
function dydx = bvpfcn(x,y,l,P,Ga,Eatilde,ha,E1tilde,h1,E2tilde,h2)
  sigma = ((4/(E1tilde*h1)+2/(E2tilde*h2))*y(2) - ha/Ga*y(4))/(6/(E1tilde*h1^2));
  d7ydx7 = Ga/ha*(4/(E1tilde*h1)+2/(E2tilde*h2))*y(6) - Eatilde/ha*12/(E1tilde*h1^3)*y(4) + (12*Eatilde*Ga/(E1tilde^2*h1^4*ha^2) + 24*Eatilde*Ga/(E1tilde*E2tilde*h1^3*h2*ha^2))*y(2);
  dydx = [y(2);y(3);y(4);y(5);y(6);y(7);d7ydx7;y(1);sigma;x*sigma];
end
function res = bcfcn(ya,yb,l,P,Ga,Eatilde,ha,E1tilde,h1,E2tilde,h2)
  d2sigma_a = ((4/(E1tilde*h1)+2/(E2tilde*h2))*ya(4) - ha/Ga*ya(6))/(6/(E1tilde*h1^2));
  d2sigma_b = ((4/(E1tilde*h1)+2/(E2tilde*h2))*yb(4) - ha/Ga*yb(6))/(6/(E1tilde*h1^2));
  res = [ya(8);yb(8)+P;ya(9);yb(9);ya(10);yb(10)-P*(h1+ha)/2;d2sigma_a;d2sigma_b;ya(2)-Ga/ha*P/(E1tilde*h1);yb(2)+Ga/ha*2*P/(E2tilde*h2)];
end
7 commentaires
  Torsten
      
      
 le 18 Avr 2023
				
      Modifié(e) : Torsten
      
      
 le 18 Avr 2023
  
			Try this code whether you get a different result.
It's the analytical solution of your equation.
% Set model parameters
l = 25;
P = 100;
Ga = 1071;
Eatilde = 3000;
ha = 0.3;
E1tilde = 1;
h1 = 5;
E2tilde = 75000;
h2 = 5;
syms x tau(x)
% Solve differential equation
eqn = diff(tau,x,7) - Ga/ha*(4/(E1tilde*h1)+2/(E2tilde*h2))*diff(tau,x,5) + Eatilde/ha*12/(E1tilde*h1^3)*diff(tau,x,3) - (12*Eatilde*Ga/(E1tilde^2*h1^4*ha^2) + 24*Eatilde*Ga/(E1tilde*E2tilde*h1^3*h2*ha^2))*diff(tau,x) == 0;
tau = dsolve(eqn)
tau0 = tau;
tau1 = diff(tau,x);
tau2 = diff(tau,x,2);
tau3 = diff(tau,x,3);
tau4 = diff(tau,x,4);
tau5 = diff(tau,x,5);
tau6 = diff(tau,x,6);
tau7 = diff(tau,x,7);
sigma = ((4/(E1tilde*h1)+2/(E2tilde*h2))*tau1 - ha/Ga* tau3)/(6/(E1tilde*h1^2));
sigma2 = diff(sigma,x,2);
% Solve for free parameters in solution from boundary conditions
cond1 = int(tau0,x,-1,1) == -P;
cond2 = int(sigma,-l,l) == 0;
cond3 = int(x*sigma,-l,l) == P*(h1+ha)/2;
cond4 = subs(sigma2,x,-l) == 0;
cond5 = subs(sigma2,x,l) == 0;
cond6 = subs(tau1,x,-l) == Ga/ha*P/(E1tilde*h1);
cond7 = subs(tau1,x,l) == -Ga/ha*2*P/(E2tilde*h2);
[A,b] = equationsToMatrix([cond1 cond2 cond3 cond4 cond5 cond6 cond7]);
coeffs = (double(A)\double(b)).';
%Insert boundary conditions in general solution
vars = symvar(tau)
tau0num = subs(tau0,vars(1:7),coeffs);
tau1num = subs(tau1,vars(1:7),coeffs);
tau2num = subs(tau2,vars(1:7),coeffs);
tau3num = subs(tau3,vars(1:7),coeffs);
tau4num = subs(tau4,vars(1:7),coeffs);
tau5num = subs(tau5,vars(1:7),coeffs);
tau6num = subs(tau6,vars(1:7),coeffs);
tau7num = subs(tau7,vars(1:7),coeffs);
sigmanum = subs(sigma,vars(1:7),coeffs);
sigma2num = subs(sigma2,vars(1:7),coeffs);
% Check solution
double(int(tau0num,x,-l,l)+P) 
double(int(sigmanum,x,-l,l))
double(int(x*sigmanum,-l,l) - P*(h1+ha)/2)
double(subs(sigma2num,x,-l))
double(subs(sigma2num,x,l))
double(subs(tau1num,x,-l)-Ga/ha*P/(E1tilde*h1))
double(subs(tau1num,x,l)+Ga/ha*2*P/(E2tilde*h2))
error = tau7num - Ga/ha*(4/(E1tilde*h1)+2/(E2tilde*h2))*tau5num + Eatilde/ha*12/(E1tilde*h1^3)*tau3num - (12*Eatilde*Ga/(E1tilde^2*h1^4*ha^2) + 24*Eatilde*Ga/(E1tilde*E2tilde*h1^3*h2*ha^2))*tau1num;
% Plot solution
figure(1)
fplot(error,[-l l])
figure(2)
fplot(tau0num,[-l l])
figure(3)
fplot(sigmanum,[-l l])
Plus de réponses (1)
  Torsten
      
      
 le 13 Avr 2023
        
      Déplacé(e) : Torsten
      
      
 le 13 Avr 2023
  
      A symbolic approach will lead you nowhere because you had to solve for the general roots of a polynomial of degree 7 which is impossible.
So think about a numerical approach.
In order to cope with the integral boundary conditions, I suggest you additionally solve for the functions
F1(y) = integral_{x=-l}^{x=y} tau dx
F2(y) = integral_{x=-l}^{x=y} sigma*x dx
by solving
dF1/dx = tau(x)
dF2/dx = sigma(x)*x
with the boundary conditions
F1(-l) = 0
F1(l) = -P
F2(-l) = 0
F2(l) = P/2 * (h_1+h_a)
Try bvp4c or bvp5c for a solution.
4 commentaires
  Torsten
      
      
 le 14 Avr 2023
				Look at the examples under
They should show you how to proceed.
If you encounter problems somewhere with your code, you can come back here to ask.
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