Efficient way to convert m by n array into a single column table with each row containing n by 1 array?

Let's say I have a 4 by 3 array:

A = [1 3 5; 2 6 7; 5 8 9; 3 2 1];

What is the fastest/most memory efficient way of converting this into a single column table with the first row containing a column array of the first row of A, the second row containing a column array of second row of A etc.

I would like to end up with something like the result of the following:

row1 = A(1, :)';
row2 = A(2, :)';
row3 = A(3, :)';
row4 = A(4, :)';

A = table({row1; row2; row3; row4})

A = 4×1 table
        Var1    
    ____________

    {3×1 double}
    {3×1 double}
    {3×1 double}
    {3×1 double}

What is the best way to automate this for an arbitrary m by n array - preferably without using a loop.

Answer 1

[Stephen23]

A = [1 3 5; 2 6 7; 5 8 9; 3 2 1];
T = cell2table(num2cell(A.',1).')

T = 4×1 table
        Var1    
    ____________

    {3×1 double}
    {3×1 double}
    {3×1 double}
    {3×1 double}