Subdividing column matrix based on two stored indices of different lengths

I have a column matrix 'A' that could be any length with any value and a coresponding column matrix of same length with whole number values within. I would like to pull values from 'A' into a new column matrix 'B' based on a column matrix of any length 'pull' where the values I pull correspond to the number in 'order rather an the row indices. I recognize this may be a confusing explanation so see the indended output in the coding section. What is a good way to do this? I can see how looping and checks could work but I would like to avoid loops if possible.

A = [0.0048;-0.001;-0.0042;0.0047;-0.00011;0.0025;0;0;0;0;0.0023;0.0004];
order =[4;5;6;7;8;9;1;2;3;10;11;12];

pull = [7;8;9;10;11;12];

%intended output
B = [0.0047;-0.00011;0.0025;0;0.0023;0.0004];

alternative values for 'pull' are shown below.

pull = [1;2;3;4;5;6];
pull = [1;7];

Answer 1

[dpb]

A = [0.0048;-0.001;-0.0042;0.0047;-0.00011;0.0025;0;0;0;0;0.0023;0.0004];
order =[4;5;6;7;8;9;1;2;3;10;11;12];

pull = [7;8;9;10;11;12];
[~,ib]=ismember(pull,order);
B=A(ib)

B = 6×1

0.0047 -0.0001 0.0025 0 0.0023 0.0004

I think your example B above is in error for the last three locations...they're the last three locations in the order array.

[Aaron DeSantis]

Thank you for catching my error in the example output.

[Aaron DeSantis]

A = [0.0048;-0.001;-0.0042;0.0047;-0.00011;0.0025;0;0;0;0;0.0023;0.0004];
order =[4;5;6;7;8;9;1;2;3;10;11;12];
%pull = [7;8;9;10;11;12];
pull = [1;2;3;4;5;6;7];
B=A(ismember(order,pull))

B = 7×1

0.0048 -0.0010 -0.0042 0.0047 0 0 0

The above output with pull redefined does not return the correct output it should be

B = [0;0;0;0.0048;-0.001;-0.0042];

[dpb]

I disagree again; 1:3 are elements 7:9 in order-->0,0,0 in A while 4:7 are 1:4 which are those returned. Your output has only six elements instead of seven.

[Aaron DeSantis]

I think there may be a misunderstanding with the intent behind my origional question.The goal is to find a way to take the given inputs:

A = [0.0048;-0.001;-0.0042;0.0047;-0.00011;0.0025;0;0;0;0;0.0023;0.0004];
order =[4;5;6;7;8;9;1;2;3;10;11;12];

and extract individual elements of A based on an array of a different length. For example the two shown below.

pull_1 = [1;2;3;4;5;6];
pull_2 = [7;8;9;10;11;12];

The key here is that the ouputs 'B_1' and 'B_2' must me in the same order as "pull". Meaning the intended outputs are:

B_1 = [0;0;0;0.0048;-0.001;-0.0042];

B_2 =[0.0047;-0.00011;0.0025;0;0.0023;0.0004];

For clarity I will provide another example going the other way:

If I want to get the output shown:

B_3 = [0.0048;-0.001;-0.0042;0;0;0];

I expect the pull_3 array used to be:

pull_3 = [4;5;6;1;2;3];

I need the outputs to be in the order because they will be used in further code. I hope this clears up any misundestanding and I apologise if you found the question misleading in any way.

[dpb]

OK, if order is important, then use (updated Answer above as well; tried to avoid the temporary ib as order wasn't specifically required in original...although I suppose it could have been inferred from the answers proposed).

A = [0.0048;-0.001;-0.0042;0.0047;-0.00011;0.0025;0;0;0;0;0.0023;0.0004];
order =[4;5;6;7;8;9;1;2;3;10;11;12];
pull = [[1;2;3;4;5;6] [7;8;9;10;11;12]];
for i=1:size(pull,2)
  [~,ib]=ismember(pull(:,i),order);
  B(:,i)=A(ib);
end
B.'

ans = 2×6

0 0 0 0.0048 -0.0010 -0.0042 0.0047 -0.0001 0.0025 0 0.0023 0.0004