Compensate the vector with the last entry

2 vues (au cours des 30 derniers jours)
DDDD
DDDD le 25 Avr 2023
I have a length L vector contains some numbers, I want to compensate this vector to length K, where K > L, with repeating the last entry of the vector. For example, the vector is [2 4 7 3], after compensate, it will be [2 4 7 3 3 3 3 3]. I hope there is an efficient way to do so because I actually have more than 10^4 vectors to compensate.
Thanks,
  2 commentaires
Stephen23
Stephen23 le 25 Avr 2023
"I hope there is an efficient way to do so because I actually have more than 10^4 vectors to compensate."
Do you really have 1e4 separate vectors stored in the workspace? How did you get them all there?
DDDD
DDDD le 31 Juil 2024
sorry for the ambiguity. I have a loop around 10^4 times, where within each loop I will need compensate the vector :)

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Stephen23
Stephen23 le 25 Avr 2023
V = [2,4,7,3];
K = 8;
V(end+1:K) = V(end)
V = 1×8
2 4 7 3 3 3 3 3

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Steven Lord
Steven Lord le 31 Juil 2024
If you were using release R2023b or later, you could use the paddata function with the Side name-value argument and either the FillValue name-value argument or the Pattern name-value argument with the 'edge' pattern.
x = [2 4 7 3]
x = 1x4
2 4 7 3
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
y = paddata(x, 7, Side = 'trailing', Pattern = 'edge')
y = 1x7
2 4 7 3 3 3 3
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
Or to show FillValue with a different value:
y = paddata(x, 7, Side = 'trailing', FillValue = -999)
y = 1x7
2 4 7 3 -999 -999 -999
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>

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