How to delete rows with values 0 from matrix

Hello,

I have matrix A which looks like

A = [0 0 0;  0 0 0;  5 1 0;  0 0 0; 1 0 3;  5 9 5;  0 0 0]

I am trying delete all rows in which all values are 0 from matrix A to get:

A = [5 1 0; 1 0 3;  5 9 5]

I used this.

for i = 1:length(A(:,1))
    while A(i,1) == 0  && A(i,2) == 0 && A(i,3) == 0
        A(i,:) = [];
    end
end

At the end it gives me matrix A but also it gives me a error:

'Index in position 1 exceeds array bounds. Index must not exceed 4.' but do not know why...

[VBBV]

A = [0 0 0;  0 0 0;  5 1 0;  0 0 0; 1 0 3;  5 9 5;  0 0 0]

A = 7×3

0 0 0 0 0 0 5 1 0 0 0 0 1 0 3 5 9 5 0 0 0

i = 1;
while i <= length(A)       
    if isequal(A(i,1),0)  & isequal(A(i,2), 0)  & isequal(A(i,3), 0)
        A(i,:) = [];   
        % tricky part lies in next line
        i = i-1;
    end    
    i = i+1 ;   
end
A

A = 3×3

5 1 0 1 0 3 5 9 5

[Simon Spielmann]

Than you a lot, it really helps!

Answer 1

[KSSV]

A = [0 0 0;  0 0 0;  5 1 0;  0 0 0; 1 0 3;  5 9 5;  0 0 0]

A = 7×3

0 0 0 0 0 0 5 1 0 0 0 0 1 0 3 5 9 5 0 0 0

A(~any(A,2),:) = []

A = 3×3

5 1 0 1 0 3 5 9 5

[Simon Spielmann]

Than you a lot, it really helps!