# Working with cell arrays

9 vues (au cours des 30 derniers jours)
L'O.G. le 5 Mai 2023
Commenté : Stephen23 le 8 Mai 2023
I would like to separate columns in an array based on the unique values of the first column. I think the way to do this is a cell array since the vectors would be of different length. Is there a way to vectorize this? For example, the following array
example = [
5 2.3 1.7
5 0.2 9.1
99 3.3 3.6
99 4.1 3.2
99 5.1 2.2
103 1.1 6.8
];
should give
A{1} = [2.3,0.2];
A{2} = [3.3,4.1,5.1];
A{3} = [1.1];
B{1} = [1.7,9.1];
B{2} = [3.6,3.2,2.2];
B{3} = [6.8];
(since there are three unique values in column 1 of the example)
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### Réponse acceptée

Paul le 5 Mai 2023
example = [
5 2.3 1.7
5 0.2 9.1
99 3.3 3.6
99 4.1 3.2
99 5.1 2.2
103 1.1 6.8
];
G = findgroups(example(:,1));
A = splitapply(@(x) mat2cell(x,numel(x)),example(:,2),G);
B = splitapply(@(x) mat2cell(x,numel(x)),example(:,3),G);
A,B
A = 3×1 cell array
{2×1 double} {3×1 double} {[ 1.1000]}
B = 3×1 cell array
{2×1 double} {3×1 double} {[ 6.8000]}
A{1}
ans = 2×1
2.3000 0.2000
B{1}
ans = 2×1
1.7000 9.1000
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Stephen23 le 8 Mai 2023
Also without the MAT2CELL call:
X = [
5 2.3 1.7
5 0.2 9.1
99 3.3 3.6
99 4.1 3.2
99 5.1 2.2
103 1.1 6.8
];
G = findgroups(X(:,1));
A = accumarray(G,X(:,2),[],@(a){a});
B = accumarray(G,X(:,3),[],@(a){a});
A,B
A = 3×1 cell array
{2×1 double} {3×1 double} {[ 1.1000]}
B = 3×1 cell array
{2×1 double} {3×1 double} {[ 6.8000]}
A{1}
ans = 2×1
2.3000 0.2000
B{1}
ans = 2×1
1.7000 9.1000

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