# Find the difference between all columns of a given row of a matrix

6 vues (au cours des 30 derniers jours)
MAWE le 8 Mai 2023
Commenté : MAWE le 8 Mai 2023
I have MXL matrix. For each row, I want to find the absolute difference between the columns, without repeating. For example, if I have a row
a = [a11 a12 a13 a14]
I want to find
[abs(a11-a12) abs(a11-a13) abs(a11-a14) abs(a12-a13) abs(a12-a14) abs(a13-a14)]
How can I do that withoug for loops?
EDIT: I found this method
pdist([2 3 1 4]',@(x,y) x-y)
which looks like what I'm looking for, but I need to extend this for a matrix, and perform the above for all rows.
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### Réponse acceptée

Antoni Garcia-Herreros le 8 Mai 2023
Hello MAWE,
You could use the function nchoosek:
Something like this might work for your case:
A=rand(4,5); % Generate data for the example
perms = nchoosek(1:size(A,2),2); % Find all the possible permutations
D=abs(A(:,perms(:,2))-A(:,perms(:,1))) % Compute the difference
D = 4×10
0.1875 0.5928 0.3519 0.1090 0.4053 0.1644 0.0785 0.2409 0.4838 0.2429 0.3220 0.2441 0.1334 0.3684 0.0779 0.4555 0.6904 0.3775 0.6125 0.2350 0.4037 0.4237 0.0883 0.1470 0.8274 0.3155 0.2568 0.5120 0.5707 0.0587 0.5416 0.0068 0.6400 0.3387 0.5348 0.0984 0.2029 0.6332 0.3319 0.3013
Hope this helps
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MAWE le 8 Mai 2023
Yes, that helped. It's exactly what I needed. Thanks!

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### Plus de réponses (1)

Luca Ferro le 8 Mai 2023
Modifié(e) : Luca Ferro le 8 Mai 2023
a=[1 3 5 -3];
aPerms=nchoosek(a,2); %generates all unique couples
absDiff=abs(aPerms(:,1)-aPerms(:,2))' %absolute difference of said couples, ' to transpose
absDiff = 1×6
2 4 4 2 6 8
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MAWE le 8 Mai 2023
Thanks, this seems to work on a vector. How can I extend to a matrix?

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