I was building an algorithm and got stuck here, I am not able to go back to the while loop after the if statement evaluates to true. Could you please help me. My code is as follows

a=input b=input

while(1)

    c=statement;[m,n]=size(c);
x=0;
    for i=1:m
        for j=1:n
            if(c(i,j)==1)
                x=x+1;
            end
        end
    end

   s=a-c;
   if (x>0)

      a=altered_a
   p=p+1;

   else
      end
   break

 end

Answer 1

[Image Analyst]

Just use the built-in function to get the skeleton:

skeletonImage = bwmorph(a, 'skel', inf);

Answer 2

[Image Analyst]

OK . . . Completely different question now that you've edited it! For this new question, if your "if" inside your while evaluates to true and you want to continue with the while loop, then change these lines:

if (x>0)
      a=altered_a
   p=p+1;

     else
     end
     break

to these lines:

if (x>0)
   a=altered_a
   p=p+1;
   % Then continue with the while loop.
else
   break; % Exit from while loop
end

[Aru hazari]

Hello thanks for the reply. But i want the control to come out of the if statement and execute the while loop for the next iteration

[Image Analyst]

And why do you think it doesn't come out of the if after it hits the p=p+1 line???? Of course it does , and then it will execute the while on the next iteration just like you want. Do you think the program just abruptly halts at that point, or breaks out of the loop? It will only leave the loop if it goes into the "else" block.

[Aru hazari]

Ah got it. Thank you