xcorr
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi
Could you please tell me how to understand the delay from the output of the numbers in the below program being displayed? I know the concept of xcorr. I am new to matlab, please help me get through this.
fs=100 t = 0:1/fs:1; x = sin(2*pi*t); y = sin(2*pi*t+pi/10); plot(t,x,t,y) [c, lags] = xcorr(x,y)
Thanks in advance
0 commentaires
Réponse acceptée
Wayne King
le 28 Oct 2011
The frequency of your inputs is 1 Hz, or 2*pi radians per second
The phase lag is pi/10 radians, which corresponds to
pi/10*(1/(2*pi)) seconds. That is 5 sample points at your sampling frequency.
Look at c for c(101:110) which corresponds to lags 0 to 10. See that the maximum value occurs at lag 5, which corresonds to 0.05 seconds as expected.
0 commentaires
Plus de réponses (0)
Voir également
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!