How to calculate horizontal and vertical correlation of an image in matlab???

4 vues (au cours des 30 derniers jours)
praveen singhal
praveen singhal le 10 Avr 2015
Commenté : Ahmed raafat le 22 Oct 2022
  • How to calculate horizontal and vertical correlation of an image in matlab???
  1 commentaire
Hyderkkk
Hyderkkk le 26 Sep 2021
IA=rgb2gray(im2double(orginal ));
c_diag = corrcoef(IA(1:end-1, 1:end-1), IA(2:end, 2:end));
c_vert = corrcoef(IA(1:end-1, :), IA(2:end, :));
c_horz = corrcoef(IA(:, 1:end-1, :), IA(:, 2:end));
figure;
subplot(3,3,1)
plot(IA(1:end-1, 1:end-1), IA(2:end, 2:end),'b'),title(sprintf('%s Horizontal Orginal image',b));
subplot(3,3,2)
plot(IA(1:end-1, :), IA(2:end, :),'b'),title(sprintf('%s Vertical Orginal image',b));
subplot(3,3,3)
plot(IA(:, 1:end-1, :), IA(:, 2:end),'b'),title(sprintf('%s Diagonal Orginal image',b));
IAA=rgb2gray(im2double(encrption));
c_diage = corrcoef(IAA(1:end-1, 1:end-1), IAA(2:end, 2:end))
c_verte = corrcoef(IAA(1:end-1, :), IAA(2:end, :))
c_horze = corrcoef(IAA(:, 1:end-1, :), IAA(:, 2:end))
subplot(3,3,4)
plot(IAA(1:end-1, 1:end-1), IAA(2:end, 2:end),'r'),title(sprintf('%s Horizontal chiphered image ',b));
subplot(3,3,5)
plot(IAA(1:end-1, :), IA(2:end, :),'r'),title(sprintf('%s Vertical chiphered image',b));
subplot(3,3,6)
plot(IAA(:, 1:end-1, :), IA(:, 2:end),'r'),title(sprintf('%s Diagonal chiphered image',b));

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Réponses (3)

elhabib
elhabib le 30 Oct 2017
% horizontal function rxy=H_correlation(image1)
P=double(image1);
x1 = double(P(:,1:end-1));
y1 = double(P(:,2:end));
randIndex1 = randperm(numel(x1));
randIndex1 = randIndex1(1:1000);
x = x1(randIndex1);
y = y1(randIndex1);
Ex=(1/(1000))*sum(x);
Ey=(1/(1000))*sum(y);
Dx=(1/(1000))*sum((x(:)-Ex).^2);
Dy=(1/(1000))*sum((y(:)-Ey).^2);
coxy=(1/(1000))*(sum((x-Ex).*(y-Ey)));
rxy=coxy/(sqrt(Dx*Dy));
% vertical
function Vxy=V_correlation(image1)
P=double(image1);
x1 = double(P(1:end-1,:));
y1 = double(P(2:end,:));
randIndex1 = randperm(numel(x1));
randIndex1 = randIndex1(1:1000);
x = x1(randIndex1);
y = y1(randIndex1);
Ex=(1/(1000))*sum(x);
Ey=(1/(1000))*sum(y);
Dx=(1/(1000))*sum((x(:)-Ex).^2);
Dy=(1/(1000))*sum((y(:)-Ey).^2);
coxy=(1/(1000))*(sum((x-Ex).*(y-Ey)));
Vxy=coxy/(sqrt(Dx*Dy));
  3 commentaires
Ankur Nandal
Ankur Nandal le 30 Août 2021
Dear Abunakar,
Please check the initialization of x1 and X2.
Ahmed raafat
Ahmed raafat le 22 Oct 2022
Thank you Sir
Thank You Very Very Much

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Mahdiyar
Mahdiyar le 10 Avr 2015
Hi singhal
May you explain more about horizontal and vertical correlation?
Regards,

praveen singhal
praveen singhal le 10 Avr 2015
Hello sir, This paper use horizontal,vertical and diagonal correlation of an image.

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