Solving a complicated symbolic equation

6 vues (au cours des 30 derniers jours)
Orel
Orel le 2 Juin 2023
Commenté : John D'Errico le 2 Juin 2023
Hello,
im trying to solve the following equation, A=B*x*sinh(x) (A and B are known constants) using symbolic toolbox:
syms x;
A=3;
B=9;
equation=A==B*x*sinh(x);
solution=solve(equation,x)
however i cannot find a solution.
i've tried using vpasolve as well but it still doesnt work.
will appreciate any advice.
  1 commentaire
John D'Errico
John D'Errico le 2 Juin 2023
solve fails, because there is no algebraic solution to your problem. However, both fzero and vpasolve will work, and the two answers you have gotten tell you that.
We cannot know why you think vpasolve failed, because we do not see what you tried. But vpasolve does not even desperately need a starting point. (It uses zero as I recall by default.) But a starting point is always a good idea.
syms x;
A=3;
B=9;
equation=A==B*x*sinh(x);
solution=vpasolve(equation,x)
solution = 
0.56248044921102851906187057960428

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Réponses (2)

Matt J
Matt J le 2 Juin 2023
Modifié(e) : Matt J le 2 Juin 2023
A=3;
B=9;
f=@(x)A-B*x*sinh(x);
[x,fval]=fzero(f,[0,10]) %first solution
x = 0.5625
fval = 1.3323e-15
[x,fval]=fzero(f,[-10,0]) %second solution
x = -0.5625
fval = 1.3323e-15

Pramil
Pramil le 2 Juin 2023
You can do the following :
syms x;
A = 3;
B = 9;
solution = vpasolve(B*x*sinh(x)==A, x, 1)
solution = 
0.56248044921102851906187057960428
The vpasolve function allows you to specify a starting value for the numerical solver, in this case, the starting value is 1. The output of this code will give you a single numerical value for x

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