if loop to save number or call NaN

I have 2 variables, both with 8 numbers in them.

I want to create a new variable which has 10 numbers in it using a for and and if loop.

• If i is present in a, save the number from b with the same index
• if i is not present in a, write NaN

This should result in a new variable c, which has 10 values in it, where 2 and 7 are presented by NaN.

Can anybody help me write this?

a = [1 3 4 5 6 8 9 10]
b = [1 2 3 3  9 7 2 2]
c = [];
for i = 1:10
    %if i is present in a, save the number from b with the same index.
    %if i is not present in a, write NaN.
end

Answer 1

[Govind KM]

The following code will give you the desired output :

a = [1 3 4 5 6 8 9 10];
b = [1 2 3 3  9 7 2 2];
c = [];
for i = 1:10
    if any(a==i)
        c(i)=b(find(a==i));
        %If a can contain duplicate elements, you can use
        %c(i)=b(find(a==i,1));
        %This will give the index of first occurrence of i in a
    else
        c(i)=NaN;
    end
end