How can I test that tab values exist in other sequence?

Hello every one

I have a problem

I want you help me

I have a vect = [ 5 34] for example

and an other sequnce that contains many values:

seq=[1 2 3 4 5 12 15 20 23 25 30 34 35 40]

how can I obtain the position of each value of vect if exist in seq

here in this exampe

the positions are:5 and 12

please hepl me!

Answer 1

[Dyuman Joshi]

vect  = [5 34];
seq=[1  2 3 4 5 12  15 20 23 25 30 34 35 40];
[~,ind] = ismember(vect, seq)

ind = 1×2

5 12

Note that this only returns the first occurence of an element in seq.

%That is, if seq has multiples of an elements, it will return the first index
seq0=[1  2 3 4 5 12  15 20 23 25 30 34 35 40 5];
%15th element of seq0 is 5, so [5 12 15] elements of seq0 are common with vect
%but it only returns 5, the first index at which 5 is found in seq0
[~,ind] = ismember(vect, seq0)

ind = 1×2

5 12

If an element is not present in the 2nd array, it will return 0 for it.

Answer 2

[Ronit]

vect = [5 34 42];
seq = [1 2 3 4 5 12 15 20 23 25 30 34 35 40];
[~, loc] = ismember(vect, seq);
disp(loc);

     5    12     0

This will give the indices of that vect element in seq and 0 if it's not present.

Answer 3

[Parag Jhunjhunwala]

There are two ways to find the position of each value of vect in seq:

1. Using find() function:

pos=zeros(1,length(vect));
for i=1:length(vect)
    if(~isempty(find(seq==vect(i), 1)))
        pos(i)=find(seq==vect(i));
    end
end

2. Using ismember() inbuilt function:

[~,pos]=ismember(vect,seq);