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Effacer les filtres

How to extract the X and Y values from a contourf graph

2 vues (au cours des 30 derniers jours)
Aidan Fishenden
Aidan Fishenden le 15 Juin 2023
Commenté : Aidan Fishenden le 15 Juin 2023
I am trying to generate a list of X and Y coordinates following the outline of a contourf graph. However, when I attempted the solutions that I found in other questions it resulted in an empty variable. Attached is my code to generate the contour graph and the resulting figure, thank you in advance for your help.
FinalMatrix = [AA AB AC AD AE AF AG AH AI AJ AK AL];
asdf = max(FinalMatrix,[],'all');
asdf = asdf*.25;
FinalMatrix(FinalMatrix<asdf) = NaN;
x = 1:12;
y = 1:7;
[X,Y] = meshgrid(x,y);
contourf(X,Y,FinalMatrix,[1 1])
[F,L] = contourf(X,Y,FinalMatrix,[1 1]);
  2 commentaires
the cyclist
the cyclist le 15 Juin 2023
Modifié(e) : the cyclist le 15 Juin 2023
It is unclear to me what you have as input. Do you have only the image (e.g. a *.jpg file?), or do you have the MATLAB *.fig file? (I assume that you do not have the original data used to create the figure, or it would be trivial.)
Can you upload what you have? You can use the paper clip icon in the INSERT section of the toolbar.
Aidan Fishenden
Aidan Fishenden le 15 Juin 2023
I do have the data used to create the figure, I've attached it here. Sorry, this is my first project with matlab.

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the cyclist
the cyclist le 15 Juin 2023
The problem is that you set the levels input to contourf to [1 1], but it is impossible to have contours there, because all your data are greater than 1. So, it makes sense that there are no contours.
If you don't set that (or set it to values where contour heights are possible), you will see the contour output.
load("matrix.mat","FinalMatrix")
x = 1:12;
y = 1:7;
[X,Y] = meshgrid(x,y);
figure
[F,L] = contourf(X,Y,FinalMatrix);
F
F = 2×129
40.0000 2.0161 2.0127 2.0000 1.7500 50.0000 5.7097 6.0000 50.0000 2.1774 2.1392 2.0000 1.4118 50.0000 5.0000 4.9012 60.0000 5.3871 6.0000 60.0000 2.3387 2.2658 2.0000 2.0000 60.0000 6.0000 5.8182 5.8947 60.0000 5.0000 4.0000 2.0161 2.0000 1.9524 1.7500 2.0000 1.0000 1.2500 4.0000 2.1774 2.0000 1.4762 1.0000 2.0000 4.8462 5.0000 2.0000 1.0000 1.5278 4.0000 2.3387 2.0000 1.0000 1.0000 3.0000 2.8095 3.0000 3.1053 2.0000 4.6538
  5 commentaires
the cyclist
the cyclist le 15 Juin 2023
OK. One thing that still makes this difficult is that we don't know enough about how general this needs to be. For example, is the spike always at the upper edge of the matrix, or might it have edges all around? We don't know what assumptions are valid.
There is probably not a simple MATLAB function to do what you want. Maybe something in the Image Processing Toolbox would make this easy, but I am not personally knowledgeable about it.
What I suggest is, before you think about coding this, is to think about the algorithm (the "instructions") that the code needs to follow. Think about each of the steps. For example, the first step might be to identify the spike itself, rather than any other values. How would you tell another person how to do that? That will help you figure out the rule, which can then be coded.
We could write code based on assumptions and guesses, but it will probably be wrong.
Aidan Fishenden
Aidan Fishenden le 15 Juin 2023
Understood, thank you.

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