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Why does polyfit gives two outputs?

6 vues (au cours des 30 derniers jours)
Rahul
Rahul le 18 Juin 2023
Commenté : the cyclist le 19 Juin 2023
Hi,
I want to plot a line passing through a set of points, which is as in the code below.
To determine the slope I used polyfit.
But it gives two outputs.
I wonder which output I should consider out of the two outputs it is giving me?
clc;
clear;
phi_1 = [0.1724*pi 0.1472*pi 2.18*pi 2.25*pi 4*pi 3.588*pi 1.012*pi 4.112*pi 4.31*pi 4.25*pi 0.832*pi];
x1 = linspace(0,1,11);
figure(1)
plot(x1,phi_1,'o');
coefficients1=polyfit(x1,phi_1,1)
coefficients1 = 1×2
7.6641 3.8373
slope1=coefficients1(1);
With regards,
rc

Réponse acceptée

Matt J
Matt J le 18 Juin 2023
Modifié(e) : Matt J le 18 Juin 2023
It doesn't give 2 outputs unless you call it with 2 output arguments. The one output that it is giving you is a vector with 2 coefficients (a slope and an intercept) because that's what a first order polynomial has.

Plus de réponses (1)

the cyclist
the cyclist le 18 Juin 2023
Modifié(e) : the cyclist le 18 Juin 2023
The first line of the function description on the documentation for polyfit states precisely what those outputs are.
They are the coefficients of the descending powers of the fitted polynomial. You asked for a 1st-order polynomial, so the first element of the output is the coefficient of the linear (1st-order) term, and the second element of the output is the coefficient of the intercept (the 0th-order term).
clc;
clear;
phi_1 = [0.1724*pi 0.1472*pi 2.18*pi 2.25*pi 4*pi 3.588*pi 1.012*pi 4.112*pi 4.31*pi 4.25*pi 0.832*pi];
x1 = linspace(0,1,11);
coefficients1=polyfit(x1,phi_1,1)
coefficients1 = 1×2
7.6641 3.8373
slope1=coefficients1(1);
intercept1=coefficients1(2)
intercept1 = 3.8373
figure(1)
hold on
plot(x1,phi_1,'o');
plot([0 1],intercept1 + slope1*[0 1])
  2 commentaires
Rahul
Rahul le 19 Juin 2023
Hi Matt & the cyclist,
Thanks a lot for your reply.It indeed helped me.
I also wish to convert x1 from linear scale to angular scale (in radians)
I can see in the documentation, probably dist is a function which can be used but I'm not sure how to implement the parameters quatA and quatB.
kindly advice.
Sincerely,
rc
the cyclist
the cyclist le 19 Juin 2023
Assuming that you are not working with quaternions, I doubt that dist is the function you need.
Please give more detail about what you are trying to do. (You might actually want to open a new question, since your original one has been answered.)

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