How to create a 3-D Cardioid shape in MatLab? (a cylinder with a cardioid base)

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Charles
Charles le 26 Juin 2023
Commenté : Charles le 27 Juin 2023
Currently, I am able to plot a 2-D cardioid in MatLab using this code:
% 2-Dimensional Cardioid
theta = linspace(0, 2*pi);
r = 1-(0.7*sin(theta));
plot(r.*cos(theta) *1.25, (r.*sin(theta) *1.25))
axis equal
xlabel('x-axis')
ylabel('y-axis')
zlabel('z-axis')
xlim([-3.5 3.5])
ylim([-3.5 3.5])
zlim([-3.5 3.5])
However, I would like to plot a 3-D cardioid, such that there is the z-dimension included.
(At the moment, the cardioid is only in 2-D, as it solely includes the x-dimension and y-dimension)
Here is the idea I want to visualize in MatLab please:
(The idea is a 3D cylinder with a cardioid-shaped base)
Is anyone able to provide some advice or insight into how to create this please? Thank you for your help.

Réponse acceptée

DGM
DGM le 26 Juin 2023
Modifié(e) : DGM le 26 Juin 2023
Here's one way.
% 2-Dimensional Cardioid
theta = linspace(0, 2*pi);
r = 1-(0.7*sin(theta));
x = r.*cos(theta)*1.25;
y = r.*sin(theta)*1.25;
% expand everything
zlevels = 10;
zrange = [-1 1];
X = repmat(x,[zlevels 1]);
Y = repmat(y,[zlevels 1]);
Z = linspace(zrange(1),zrange(2),zlevels);
Z = repmat(Z.',[1 numel(x)]);
% plot using surf()
hs = surf(X,Y,Z);
hs.FaceColor = [0.65 0.6 1];
hl = lightangle(gca,45,45);
material(hs,[0.5 1 1])
set(gca,'projection','perspective')
view([-46 38])
axis equal
xlabel('x-axis')
ylabel('y-axis')
zlabel('z-axis')
xlim([-2 2])
ylim([-2.5 1.5])
zlim([-2 2])
You'll probably want to play with the colormapping and lighting as you see fit.
  4 commentaires
DGM
DGM le 26 Juin 2023
I was just trying to approximate the figure setup that would have been used to create the sample image. All of the additional fluff (lighting, color, projection) can simply be omitted.
% 2-Dimensional Cardioid
theta = linspace(0, 2*pi);
r = 1-(0.7*sin(theta));
x = r.*cos(theta)*1.25;
y = r.*sin(theta)*1.25;
% expand everything
zlevels = 10;
zrange = [-1 1];
X = repmat(x,[zlevels 1]);
Y = repmat(y,[zlevels 1]);
Z = linspace(zrange(1),zrange(2),zlevels);
Z = repmat(Z.',[1 numel(x)]);
% plot using surf()
surf(X,Y,Z);
axis equal
xlabel('x-axis')
ylabel('y-axis')
zlabel('z-axis')
xlim([-2 2])
ylim([-2.5 1.5])
zlim([-2 2])
Charles
Charles le 27 Juin 2023
Awesome! Thank you, this is great!

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Dyuman Joshi
Dyuman Joshi le 26 Juin 2023
Modifié(e) : Dyuman Joshi le 26 Juin 2023
Use the implicit equation of Cardiod as input to fimplicit3 and define x, y and z limits required -
% 2-Dimensional Cardioid
a = 1.25;
%Equation referenced from Wikipedia, not the same as used above
eqn = @(x,y,z) (x.^2+y.^2).^2 + 4.*a.*x.*(x.^2+y.^2) - 4.*a^2.*y.^2;
%The intervals defined are [xmin xmax ymin ymax zmin zmax]
fimplicit3(eqn, [-2*pi 2*pi -5 5 -2 2])
xlabel('x-axis')
ylabel('y-axis')
zlabel('z-axis')

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