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Access varying variable names in loop

10 vues (au cours des 30 derniers jours)
Oskar Kilgus
Oskar Kilgus le 27 Juin 2023
Commenté : Steven Lord le 28 Juin 2023
Hi,
i set up an 8x19 array with numbers varying from 4 to 152, including zeros. (numbering)
I now want to fill a cell-array with data (currently stored in struct array). These struct arrays are named something_numbering, where the number is one of those from 4 to 152.
I tried the following (which obviously did not work):
for m=1:8
for n=1:19
if numbering ~= 0 %check if 8x19 array with numbers is nonzero
data_vector{m,n} = something_('%03d',numbering(m,n)).something.something;
end
end
end
The problem is to include the varying numbering and to maintain the structure of the numbering array.
To make things more precise let me provide you with a minimal example:
numbering = [1 5 23; 0 7 24; 0 9 0]
% i now want the data-array to be
data_vector = [something_001 something_005 something_023;
0 something_007 something_024;
0 something_009 0]
Happy for any help! Cheers
  6 commentaires
Stephen23
Stephen23 le 28 Juin 2023
Modifié(e) : Stephen23 le 28 Juin 2023
"another problem is, that the .mat files are all named with numbers in front so i cant import them directly can i?"
I don't see why that would be a problem, this is very common. I routinely import many thousands of data files which have all kinds of numbers in the filenames. Filenames are rather irrelevant to what you can import.
"My intent is to load all these .mat files in a way, that i can easily access the vectors in the "second layer" of the struct-arrays in, lets say a for loop. This way i can ease my data-analysis (e.g. FFT analysis)"
I strongly recommend to import them into one array. From your description, a non-scalar structure might be a good option. That would make it eas to keep all of the imported data together along with the corresponding filenames, etc.
From the non-scalar structure you can simply loop over the elements, etc, and use convenience syntaxes:
Hopefully all of the structures saved within the MAT files have the same name (simpler, more robust, more efficient to process) and not a different name in each MAT file (... ugh, that would be very... unfortunate).
Hopefully the structure fields also have the same names, then merging them together will be easier.
Please upload some sample MAT files by clicking the paperclip button.
In lieu of that, as far as I can tell you have something like this (structures saved in MAT files):
S = struct('X',1:3,'Y','A'); save test1.mat S
S = struct('X',4:6,'Y','B'); save test2.mat S
S = struct('X',7:9,'Y','C'); save test3.mat S
which is easy to import in a loop:
P = '.'; % absolute/relative path to where the files are saved
S = dir(fullfile(P,'*.mat'));
for k = 1:numel(S)
F = fullfile(P,S(k).name);
D = load(F);
D.S.name = F;
S(k).data = D.S;
end
D = [S.data] % all file data
D = 1×3 struct array with fields:
X Y name
vertcat(D.X) % all X data in one matrix
ans = 3×3
1 2 3 4 5 6 7 8 9
{D.name}.' % corresponding filenames
ans = 3×1 cell array
{'./test1.mat'} {'./test2.mat'} {'./test3.mat'}
Simplify the data design and you make processing it much easier and more efficient. The name "MATLAB" comes from "MATrix LABoratory". MATLAB is designed so that working with matrices and arrays is the best approach (not splitting up the data into lots of separate variables and making the data harder to work with).
Steven Lord
Steven Lord le 28 Juin 2023
edit: another problem is, that the .mat files are all named with numbers in front so i cant import them directly can i?
If you're calling load on a MAT-file whose name starts with numbers in front that's no problem. If you're calling load to read data from a text file in a format load can handle (created with save -ascii for example) then MATLAB would need to create a variable whose name is a modified version of the text file name that is a valid MATLAB identifier.
cd(tempdir)
x = 1:10;
y = x.^2;
save('123mat.mat', 'x', 'y')
The data was stored as expected in the MAT-file.
whos -file 123mat.mat
Name Size Bytes Class Attributes x 1x10 80 double y 1x10 80 double
Calling load to read it into a struct array works fine.
data = load('123mat.mat')
data = struct with fields:
x: [1 2 3 4 5 6 7 8 9 10] y: [1 4 9 16 25 36 49 64 81 100]
Calling load without an output argument risks overwriting variables that already exist in the workspace. You might expect z to be [42; 3+4i] in the code below; it's not. [If 123mat.mat had not contained variables named x or y it would have.]
x = 42;
y = 3+4i;
load('123mat.mat')
z = [x; y]
z = 2×10
1 2 3 4 5 6 7 8 9 10 1 4 9 16 25 36 49 64 81 100
Now let's look at a text file. The data looks like it was written correctly in the file (the format of the numbers is a bit different, but the values are the same as we'll see at the end looking at the variable q.)
save('123mat.txt', '-ascii', 'x', 'y')
type 123mat.txt
1.0000000e+00 2.0000000e+00 3.0000000e+00 4.0000000e+00 5.0000000e+00 6.0000000e+00 7.0000000e+00 8.0000000e+00 9.0000000e+00 1.0000000e+01 1.0000000e+00 4.0000000e+00 9.0000000e+00 1.6000000e+01 2.5000000e+01 3.6000000e+01 4.9000000e+01 6.4000000e+01 8.1000000e+01 1.0000000e+02
If we call load with no outputs MATLAB doesn't create a variable named 123mat in the workspace. It can't since that's not a valid variable name. But it creates something close.
clear all
load 123mat.txt
whos
Name Size Bytes Class Attributes X123mat 2x10 160 double
Where does that variable name come from? See the Algorithms section of the load documentation page.
But if we call load with an output that works fine.
q = load('123mat.txt')
q = 2×10
1 2 3 4 5 6 7 8 9 10 1 4 9 16 25 36 49 64 81 100

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Réponses (1)

Jacob Mathew
Jacob Mathew le 27 Juin 2023
Hi Oskar,
I can point you towards a simple example and hope you can build from it. Conside the code below:
x = 'hello'; % Dynamic content
myStruct = struct('hello', 'world'); % Struct with a field 'name'
fieldValue = myStruct.(x)
fieldValue = 'world'

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