Error using strfind Conversion to double from table is not possible.

2 vues (au cours des 30 derniers jours)
I have a table and I extracted one value from the table and it is
dataTimeColumn(1,1) = 2023-07-24T16:15:54.200
And I tried to find T in this by using strfind like this.
temp2 = strfind(dataTimeColumn(1,1),'T')
and when I run I get the error
Error using strfind
Conversion to double from table is not possible.
Why is that and how can I solve it. Thank you.

Réponse acceptée

Star Strider
Star Strider le 25 Juil 2023
It is apparently not an actual datetime variable (array). Instead of searching for the ‘T’ occurrences, convert it to datetime instead —
dataTimeColumn(1,1) = datetime('2023-07-24T16:15:54.200', 'InputFormat','yyyy-MM-dd''T''HH:mm:ss.SSS', 'Format','yyyy-MM-dd HH:mm:ss.SSS')
dataTimeColumn = datetime
2023-07-24 16:15:54.200
.

Plus de réponses (1)

Walter Roberson
Walter Roberson le 25 Juil 2023
temp2 = strfind(dataTimeColumn{1,1},'T')

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