Effacer les filtres
Effacer les filtres

create a new array with group sum

3 vues (au cours des 30 derniers jours)
Igenyar
Igenyar le 28 Juil 2023
Commenté : Igenyar le 28 Juil 2023
I have the following data.
1690492071 238581 1.3
1690492071 238582 1.0
1690492071 238580 0.3
1690492071 238576 0.0
1690492071 238577 0.0
1690492071 238579 0.0
1690492071 238583 0.0
1690492071 238584 0.0
1690492071 238585 0.0
1690492071 238586 0.0
1690492076 238581 1.7
1690492076 238582 1.3
1690492076 238576 0.0
1690492076 238577 0.0
1690492076 238579 0.0
1690492076 238580 0.0
1690492076 238583 0.0
1690492076 238584 0.0
1690492076 238585 0.0
1690492076 238586 0.0
...
The first column is the group id and the third column is the value I want to sum for each group. The result should be:
1690492071 2.6
1690492076 3.0
...
I have been struggling for hours, really appreciate help given.

Réponse acceptée

Walter Roberson
Walter Roberson le 28 Juil 2023
data = [ ...
1690492071 238581 1.3
1690492071 238582 1.0
1690492071 238580 0.3
1690492071 238576 0.0
1690492071 238577 0.0
1690492071 238579 0.0
1690492071 238583 0.0
1690492071 238584 0.0
1690492071 238585 0.0
1690492071 238586 0.0
1690492076 238581 1.7
1690492076 238582 1.3
1690492076 238576 0.0
1690492076 238577 0.0
1690492076 238579 0.0
1690492076 238580 0.0
1690492076 238583 0.0
1690492076 238584 0.0
1690492076 238585 0.0
1690492076 238586 0.0];
[totals, groups] = groupsummary(data(:,3), data(:,1), "sum");
format long g
results = [groups, totals]
results = 2×2
1.0e+00 * 1690492071 2.6 1690492076 3
  1 commentaire
Igenyar
Igenyar le 28 Juil 2023
That's work great, thank you!

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Paul
Paul le 28 Juil 2023
Check out splitapply

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