abs cannot be used in problem-based optimization expression

1 vue (au cours des 30 derniers jours)
Bruno Luong
Bruno Luong le 29 Juil 2023
Commenté : Bruno Luong le 29 Juil 2023
Can someone tell me why I cannot use abs() in this simple setup.
prob = optimproblem();
x = optimvar('x',1,1);
y = 1;
x0 = struct('x',0);
prob.Objective = abs(x-y); % sum(abs(x-y)) also doesn't work
Incorrect number or types of inputs or outputs for function 'abs'.
%prob.Objective = norm(x-y,1); % this however works
sol = solve(prob,x0)
If I use prob.Objective = norm(x-y,1) it wokks just fine

Réponse acceptée

Bruno Luong
Bruno Luong le 29 Juil 2023
  2 commentaires
Torsten
Torsten le 29 Juil 2023
sqrt((x-y).^2) doesn't seem to work, either.
Bruno Luong
Bruno Luong le 29 Juil 2023
Syntaxically it works, but I have to add a small margin to avoid singularity of the derivative at 0
prob = optimproblem();
x = optimvar('x',1,1);
y = 1;
x0 = struct('x',0);
prob.Objective = sqrt((x-y).^2+eps); % sum(abs(x-y)) also doesn't work
sol = solve(prob,x0)
Solving problem using fminunc. Local minimum found. Optimization completed because the size of the gradient is less than the value of the optimality tolerance.
sol = struct with fields:
x: 1

Connectez-vous pour commenter.

Plus de réponses (0)

Produits


Version

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by