creat stateflow use script

4 vues (au cours des 30 derniers jours)
wenchao zhang
wenchao zhang le 14 Août 2023
Commenté : wenchao zhang le 14 Août 2023
hello,when i run the following script,error happens, any one knows what the root reason, following are the script.
sfnew
rt = sfroot;
ch = find(rt,'-isa','Stateflow.Chart');
st = Stateflow.State(ch);
view(st)
j1 = Stateflow.Junction(ch);
j1.Position.Radius = 16.18;
j1.Position.Center = [31.41 27.18];
j2 = Stateflow.Junction(ch);
j2.Position.Radius = 16.18;
j2.Position.Center = [62.41 27.18];
transition = Stateflow.Transition(ch);
transition.Source = j1;
transition.Destination = j2;
transition.LabelString = '{xx;yy;zz;}';
  2 commentaires
Fangjun Jiang
Fangjun Jiang le 14 Août 2023
No error in R2022b. What is the error message?
wenchao zhang
wenchao zhang le 14 Août 2023
ok,thanks,may be it is caused by lost the state flow license, tomorrow i will check again. may be some command not supported in 2019a, not sure

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