How to find the intersection values of line and curve?
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
How to find the intersection values of line(black) and the curve(blue)
clc
close all
d1 = 0.4;d2 = 0.6;d = d1 + d2; n1 = 3.46;n2 = 1.5;
lambda = linspace(400e-3,800e-3, 100000); w=2*pi./lambda;
D1 = (2*pi*n1*d1)./lambda;D2 = (2*pi*n2*d2)./lambda;
RHS = cos(D1).*cos(D2) - 0.5*(n1^2+n2^2)/(n1*n2) * sin(D1) .*sin(D2);
plot(w,RHS)
hold on
yline(-1); hold off
hold on
yline(1); hold off
0 commentaires
Réponse acceptée
Star Strider
le 22 Août 2023
Try this —
% clc
% close all
d1 = 0.4;d2 = 0.6;d = d1 + d2; n1 = 3.46;n2 = 1.5;
lambda = linspace(400e-3,800e-3, 100000); w=2*pi./lambda;
D1 = (2*pi*n1*d1)./lambda;D2 = (2*pi*n2*d2)./lambda;
RHS = cos(D1).*cos(D2) - 0.5*(n1^2+n2^2)/(n1*n2) * sin(D1) .*sin(D2);
yl = [-1 1];
for k = 1:numel(yl)
[xi{k},yi{k}] = intsx(w, RHS, yl(k));
end
figure
plot(w,RHS)
hold on
for k = 1:numel(yl)
plot(xi{k}, yi{k}, 'rs')
end
yline(-1)
yline(1)
hold off
function [xi,yi] = intsx(x,y,c) % Simple Intersection Function
% ARGUMENTS: (x,y): Vectors, c: Constant
zci = find(diff(sign(y-c)));
for k = 1:numel(zci)
idxrng = max(1,zci(k)-1) : min(numel(x),zci(k)+1);
xi(k,:) = interp1(y(idxrng)-c,x(idxrng),0);
yi(k,:) = interp1(x(idxrng), y(idxrng), xi(k));
end
end
.
2 commentaires
Star Strider
le 22 Août 2023
As always, my pleasure!
They already are for each line value (-1,+1) intersection.
To get them all in one array, concatenate them and sort it by the ‘x’ value:
% clc
% close all
d1 = 0.4;d2 = 0.6;d = d1 + d2; n1 = 3.46;n2 = 1.5;
lambda = linspace(400e-3,800e-3, 100000); w=2*pi./lambda;
D1 = (2*pi*n1*d1)./lambda;D2 = (2*pi*n2*d2)./lambda;
RHS = cos(D1).*cos(D2) - 0.5*(n1^2+n2^2)/(n1*n2) * sin(D1) .*sin(D2);
yl = [-1 1];
for k = 1:numel(yl)
[xi,yi] = intsx(w, RHS, yl(k));
xv{k,:} = xi;
yv{k,:} = yi;
end
Intersections = array2table(sortrows(cell2mat([xv yv]),1), 'VariableNames',{'x','y'})
figure
plot(w,RHS)
hold on
for k = 1:numel(yl)
plot(xv{k}, yv{k}, 'rs')
end
yline(-1)
yline(1)
hold off
function [xi,yi] = intsx(x,y,c) % Simple Intersection Function
% ARGUMENTS: (x,y): Vectors, c: Constant
zci = find(diff(sign(y-c)));
for k = 1:numel(zci)
idxrng = max(1,zci(k)-1) : min(numel(x),zci(k)+1);
xi(k,:) = interp1(y(idxrng)-c,x(idxrng),0);
yi(k,:) = interp1(x(idxrng), y(idxrng), xi(k));
end
end
The relevant previous function is interp1, and the relevant new functions are cell2mat, sortrows, and array2table.
.
Plus de réponses (1)
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!