Optimization of a script

1 vue (au cours des 30 derniers jours)
Alcide
Alcide le 24 Août 2023
Hi,
I'm working on a script like this:
a=[ 1 1 0 1 1 1 1 0 1]
b=2
c=3.2
v=0
for i=1: 9
f=b*2^(i-1)
if a(i)==0
g=f*c-f
v=v+g
end
end
I would like to maximize the value of v using b and c as variables.
How can i do that?
TY
  2 commentaires
Dyuman Joshi
Dyuman Joshi le 24 Août 2023
Do you mean - you want to find value of b and c for which v will be maximum?
Torsten
Torsten le 24 Août 2023
b = c = Inf

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Bruno Luong
Bruno Luong le 24 Août 2023
The v you compute is simply
132*b*(c-1)
You want to optimiza it? Take b=Inf and c=Inf

Plus de réponses (1)

Kevin Holly
Kevin Holly le 24 Août 2023
Modifié(e) : Kevin Holly le 24 Août 2023
You can use fmincon.
a = [1 1 0 1 1 1 1 0 1];
b0 = 2; % Initial guess for b
c0 = 3.2; % Initial guess for c
% Define the objective function to maximize
objective = @(x) -calculateV(a, x(1), x(2));
% Set the lower and upper bounds for the variables
lb = [0, 0]; % Lower bounds for b and c
ub = [Inf, Inf]; % Upper bounds for b and c
% Perform constrained optimization to maximize v
[x, fval] = fmincon(objective, [b0, c0], [], [], [], [], lb, ub);
Problem appears unbounded. fmincon stopped because the objective function value is less than the value of the objective function limit and constraints are satisfied to within the value of the constraint tolerance.
% Retrieve the optimized values
b_optimized = x(1);
c_optimized = x(2);
v_maximized = -fval;
% Display the optimized values and the corresponding v
disp("Optimized Values:")
Optimized Values:
disp("b = " + b_optimized)
b = 10167158107334.54
disp("c = " + c_optimized)
c = 10639554538105.3
disp("Maximized v = " + v_maximized)
Maximized v = 1.4278972379828e+28
% Function to calculate v for given a, b, and c
function v = calculateV(a, b, c)
v = 0;
for i = 1:numel(a)
f = b * 2^(i-1);
if a(i) == 0
g = f * c - f;
v = v + g;
end
end
end

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