Make a vector into a call of a function

Hi, i would like to use bi2de for some elements of a vector A. If A(1)=0 A(2)=0 A(3)=1 and i call bi2de as bi2de(A(1:3)) i get the dec of each element A(1) A(2) and A(3). I would like to take the dec of bi2de([A(1) A(2) A(3)]). How can i create this vector for random number of elements in [ ] without creating the vector before for example using while-loop. thanks

Answer 1

[Stephen23]

According to your definition

A(1)=0 A(2)=0 A(3)=1

then we get

A = [0,0,1]

which means we can simply call

bi2de(A)

Whatever method you use it will have to create a vector (or matrix) before these values are passed to bi2de.

[Nikos Karamolegkos]

sure, but A has length larger than 3. If A has size 1x12 i want to take first 3 values or 2 or 5, not all the vector, so i have to create a sub-vector every time with this way [A(1) A(2) ... A(something)]. I want a not hard coded method.

[Stephen23]

Then you can use basic MATLAB indexing, e.g. to use the first three elements of A:

N = 3;
bi2dec(A(1:N))

Or do you imagine something else? If so, please explain with examples of what you would like to have as input and outputs.

[Nikos Karamolegkos]

thanks for your responce. First i am using bi2de , second if i try bi2de(A(1:something)) and A has the values A(1)=0 A(2)=0 and A(3)=1 then i have as result a vector with 3 elements. The first element is 0 the second is 0 and the third is 1. That means that bi2de is running for each element of A(1:3) (think it as 3-loops) i want this to run one time such as call her for vector [A(1) A(2) A(3)]=[0 0 1]=4 (bi2de has msb the last (right element)) doing this one value is returned. Is it now clear?

[Guillaume]

No, it's really not clear. Note that

A(1:3)

is exactly the same as

 [A(1) A(2) A(3)]

assuming A is a row vector.

If A is a column vector or matrix then,

A(1:3).'

is exactly the same

[Nikos Karamolegkos]

of course let me try to be more specific. I have a function bi2de (check help) i have a vector A size lets tell 12. if i write: -bi2de(A(1)) i will take 0 -bi2de(A(2)) i will take 0 -bi2de(A(3)) i will take 1

that is exactly the same as writing bi2de(A(1:3)) i will take a new vector that will be 0, 0, 1

I don't want this. I want to be give A(1) A(2) A(3) as one bin value the value 001. If i make it hard coded as temp=[A(1) A(2) A(3)] and write bi2de(temp) the function will return one time (one value) that it will be 4 (i explained the reason before). I want to create the vector temp not hard coded but automatically for random-but-known end_index value. for example temp=[A(1) A(2) A(3) ... A(end_index)] that can be 000100 and call bi2de for 00010 and take one returned value. Try to call bi2de it will help.

[Stephen23]

"-bi2de(A(1)) i will take 0 -bi2de(A(2)) i will take 0 -bi2de(A(3)) i will take 1, that is exactly the same as writing bi2de(A(1:3))"

Except that these are not the same same thing, if A is a row vector. Try it. Your confusion might be happening because you have a column vector for A: is A a column vector? What do you get if you call this?:

size(A)

The vector-orientation is very important, as will be clear when you read the documentation and try some examples:

>> bi2de([0,0,1])
ans =
     4
>> bi2de([0;0;1])
ans =
     0
     0
     1

"I want to be give A(1) A(2) A(3) as one bin value the value 001"

Which is exactly how bi2de treats a horizontal vector input, in which case you can use any of my suggested solutions. If your input vector A is a column vector, then the function bi2de will treat each row as a separate value to convert, as the documentation clearly states. You can simply transpose the input vector to turn it into a horizontal vector if you want it considered as one value:

>> A = randi([0,1],12,1)
A =
     0
     0
     1
     1
     0
     0
     0
     1
     1
     1
     0
     1
>> bi2de(A(1:3)) % each row as separate value
ans =
     0
     0
     1
>> bi2de(A(1:3).') % transposed into row vector
ans =
     4

[Nikos Karamolegkos]

it is working thanks. i forgot basic things