Multiple moving points in an area with the given velocity
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
How to write a code for random number of points moving in an area at a given velocity.
There are random number of points ( 50) in an area of 600*600, moving from one point to another at given velocity (10m/s).
The code for moving one point in an area of 25*25 is given below. Similarly I want to move random number (>=50) of points in the given area (600*600).
clc
close all
figure;axis square;
set(gca,'XLim',[0,25],'YLim',[0,25]);
MOVINGPOINT = rectangle('Parent',gca,'Position',[4.5,4.5,1,1],'Curvature',[1,1]);
startPos = [2,2];
endPos = [20,20];
vel = 10;
[x_dis] = endPos(1)-startPos(1);
[y_dis] = endPos(2)-startPos(2);
Dis = sqrt(x_dis^2+y_dis^2);
Ttime = Dis/vel;
x_vel = (vel*x_dis)/Dis;
y_vel = (vel*y_dis)/Dis;
t = 0.01:0.01:Ttime;
X =startPos(1)+x_vel*t;
Y = startPos(1)+y_vel*t;
trajectory = [X;Y];
for frameNo = 1:length(t)
set(MOVINGPOINT,'Position',[trajectory(1,frameNo)-0.25,trajectory(2,frameNo)-0.25,0.5,0.5]);
frames(frameNo) = getframe;
end
Please help me with the random number (>=50) of points moving with the given velocity and to calculate the trajectory of the points.
0 commentaires
Réponses (2)
recent works
le 30 Août 2023
Modifié(e) : Voss
le 30 Août 2023
Moving random number of points in an area at a given velocity:
clc
close all
% Define the area of movement
x_min = 0;
x_max = 600;
y_min = 0;
y_max = 600;
% Generate random number of points
num_points = 50;
points = rand(num_points, 2)*(x_max-x_min) + x_min;
% Define the velocity
vel = 10;
% Calculate the trajectory of the points
trajectory = zeros(num_points, 3);
for i = 1:num_points
[x_dis, y_dis] = points(i, :) - points(i, 1:end-1);
Dis = sqrt(x_dis^2+y_dis^2);
Ttime = Dis/vel;
x_vel = (vel*x_dis)/Dis;
y_vel = (vel*y_dis)/Dis;
t = 0.01:0.01:Ttime;
trajectory(i, 1:end) = points(i, :) + x_vel*t;
end
% Plot the trajectory of the points
figure;
plot(trajectory(:, 1), trajectory(:, 2));
Voss
le 30 Août 2023
Here the start and end position of each point is random; therefore the trajectories and start-to-end distances are random, but since all points move at the same speed, the time taken to go from start position to end position is different for different points. If a point gets to its end position before other points then it stays there until all points are done moving (at which time the program is done running).
figure;
ax = gca();
vel = 10;
x_min = 0;
x_max = 600;
y_min = 0;
y_max = 600;
Npts_min = 50;
Npts_max = 100;
Npts = randi([Npts_min Npts_max]);
points = plot(NaN(2,Npts),NaN(2,Npts),'.');
set(ax,'XLim',[x_min x_max],'YLim',[y_min y_max]);
axis square
startPos = rand(Npts,2).*[x_max-x_min y_max-y_min]+[x_min y_min];
endPos = rand(Npts,2).*[x_max-x_min y_max-y_min]+[x_min y_min];
x_dis = endPos(:,1)-startPos(:,1);
y_dis = endPos(:,2)-startPos(:,2);
Dis = sqrt(x_dis.^2+y_dis.^2);
Ttime = Dis/vel;
x_vel = vel*x_dis./Dis;
y_vel = vel*y_dis./Dis;
t = 0.01:0.01:max(Ttime);
t = min(t,Ttime);
X = startPos(:,1)+x_vel.*t;
Y = startPos(:,2)+y_vel.*t;
trajectory = permute(cat(3,X,Y),[1 3 2]);
trajectory_cell = num2cell(trajectory);
for frameNo = 1:size(t,2)
set(points,{'XData','YData'},trajectory_cell(:,:,frameNo));
drawnow
end
0 commentaires
Voir également
Catégories
En savoir plus sur Orange dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!