How can i extract the values in complex double array

I have the below complex double array, when i want to extract the fourth value and the ones which are above of the fourth one (like H(5) H(6) H(7) ....) Matlab says " All zero sparse: 1×1". so How can i extract them ?
H=
(1,1) -0.0181 - 0.0365i
(2,1) 0.2017 - 0.0552i
(3,1) 0.0795 - 0.0786i
(2,2) -0.0173 - 0.0370i
(3,2) 0.2023 - 0.0551i
(4,2) 0.0794 - 0.0785i
(3,3) -0.0166 - 0.0374i
(4,3) 0.2028 - 0.0551i
(5,3) 0.0793 - 0.0785i
(4,4) -0.0158 - 0.0378i
(5,4) 0.2034 - 0.0550i
(6,4) 0.0793 - 0.0784i
(5,5) -0.0151 - 0.0383i
(6,5) 0.2040 - 0.0549i

2 commentaires

Do you mean extract the fourth non-zero value? In memory order? Please post an example input and exact output you want.
hello
according to your post H would be a 2D and not 1D arry so when you say the fourth and above index is fine for a 1D array but I don't know what you need to extract for a 2D array
H(1,1) = -0.0181 - 0.0365i;
H(2,1) = 0.2017 - 0.0552i;
H(3,1) = 0.0795 - 0.0786i;
H(2,2) = -0.0173 - 0.0370i;
H(3,2) = 0.2023 - 0.0551i;
H(4,2) = 0.0794 - 0.0785i;
H(3,3) = -0.0166 - 0.0374i;
H(4,3) = 0.2028 - 0.0551i;
H(5,3) = 0.0793 - 0.0785i;
H(4,4) = -0.0158 - 0.0378i;
H(5,4) = 0.2034 - 0.0550i;
H(6,4) = 0.0793 - 0.0784i;
H(5,5) = -0.0151 - 0.0383i;
H(6,5) = 0.2040 - 0.0549i;
imagesc(abs(H));colorbar('vert')

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Réponses (1)

You can achieve this using logical indexing and comparison of the magnitudes of the complex values. Here's how you can extract the fourth value and the values above it in MATLAB:
% Given complex array H
H = [
-0.0181 - 0.0365i
0.2017 - 0.0552i
0.0795 - 0.0786i
-0.0173 - 0.0370i
0.2023 - 0.0551i
0.0794 - 0.0785i
-0.0166 - 0.0374i
0.2028 - 0.0551i
0.0793 - 0.0785i
-0.0158 - 0.0378i
0.2034 - 0.0550i
0.0793 - 0.0784i
-0.0151 - 0.0383i
0.2040 - 0.0549i
];
% Extract the fourth value
fourth_value = H(4);
% Find the indices of values above the fourth value
above_fourth_indices = abs(H) > abs(fourth_value);
% Extract the values above the fourth value
values_above_fourth = H(above_fourth_indices);
% Display the results
disp('Fourth Value:');
disp(fourth_value);
disp('Values Above Fourth Value:');
disp(values_above_fourth);

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R2022b

Question posée :

le 30 Août 2023

Commenté :

le 30 Août 2023

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