what's wrong with my ks test?

4 vues (au cours des 30 derniers jours)
Kalle
Kalle le 24 Sep 2023
Commenté : Kalle le 24 Sep 2023
I get too high D-values with my ks-test but at the same time low p-values. How is that possible?
C = wblrnd(100,1);
C = C';
% 3 parameter WEIBULL SETUP
custompdf = @(x,a,b,c) (x>c).*(b/a).*(((x-c)/a).^(b-1)).*exp(-((x-c)/a).^b);
customcdf = @(x,a,b,c) (x>c).*1-exp(-((x-c)/a).^b);
opt = statset('MaxIter',1e5,'MaxFunEvals',1e5,'FunValCheck','off');
params = mle(C,'pdf',custompdf,'start',[mean(C) std(C) min(C)],'Options',opt,'LowerBound',[0 0 -Inf],'UpperBound',[Inf Inf min(C)]);
a_Welle = params(1,1);
b_Welle = params(1,2);
c_Welle = params(1,3);
x = [c_Welle+eps(c_Welle):0.1:max(C)*mean(C)];
% 2 parameter WEIBULL SETUP
p = wblfit(C);
[nlogl,pcov] = wbllike(p,C);
[quantile_Wbl2,q95lo,q95up] = wblinv(0.99958333,p(1),p(2),pcov);
Q = quantile(customcdf(x, a_Welle, b_Welle, c_Welle),0.99958333);
% kolmogorov-smirnov
[h_wbl3,p_wbl3,ksstat_wbl3] = kstest2(C, customcdf(C,a_Welle,b_Welle,c_Welle));
[h_wbl2,p_wbl2,ksstat_wbl2] = kstest2(C, wblcdf(C,p(1),p(2)));
fprintf('Two parameter Weibull-Distr.: h = %d, p = %f, D-Wert = %f\n', h_wbl2, p_wbl2, ksstat_wbl2);
Two parameter Weibull-Distr.: h = 0, p = 0.289041, D-Wert = 1.000000
fprintf('three parameter Weibull-Distr.: h = %d, p = %f, D-Wert = %f\n', h_wbl3, p_wbl3, ksstat_wbl3);
three parameter Weibull-Distr.: h = 0, p = 0.289041, D-Wert = 1.000000
How can I improve my code?

Réponse acceptée

the cyclist
the cyclist le 24 Sep 2023
My guess here is that this line of code
C = wblrnd(100,1);
is not doing what you expect. It is generating just one value, from a Weibull distribution with parameters a=100, b=1. Take a look the documentation for wblrnd, to find the syntax for what you want to do. I expect you wanted something like
C = wblrnd(4,3,100,1);
  1 commentaire
Kalle
Kalle le 24 Sep 2023
Owww, how embarrassing! thank you!

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