Replace char with other and count total numbers
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Hello, I need some help.
1. I want to replace in string all the \n with whitespaces. I have already tried strrep(temp_str,'\n',' '); but it doesn't work!!
2. I want to count the number of zeros and ones in cells. For instance at the upper image i want as result number_of_zeros=3
number_of_ones=12
is there and way to do this?
Réponses (4)
pfb
le 13 Avr 2015
I do not see the relevance of strings or newline chars.
What is the object you're showing? What is the result of
whos x
where x is the object you represent graphically? If you could concatenate all of the vectors in "column" 2 into a single vector, say y, then the number of ones would be O=sum(y) and the number of zeros Z = length(y)-O.
3 commentaires
pfb
le 13 Avr 2015
I'm not sure whether you have a cell with 2 columns... I do not use that graphical inspector.
Assuming it is a cell with 2 columns, and it is called x , try
O = sum(cell2mat(x(:,2)'));
Z = length(cell2mat(x(:,2)'))-O;
xaroula mav
le 14 Avr 2015
Image Analyst
le 14 Avr 2015
Go ahead and mark the answer as "Accepted" so he/she gets reputation points.
1. this example might help you with your whitespace problem
str = 'hello\nworld';
formattedStr = sprintf(str)
newlineChar = sprintf('\n');
strrep(formattedStr,newlineChar,' ')
2. you can get number of zeros and ones by the following:
if your variable is x, then
number_of_ones = sum([x{:,2}]);
number_of_zeros = length([x{:,2}]) - number_of_ones;
3 commentaires
xaroula mav
le 13 Avr 2015
tdd4c1
le 14 Avr 2015
It appears that you are working with cell arrays. Make sure you use the curly braces and square brackets (not parens) when executing this code (e.g. [x{:,2}]). If this still doesn't work, post how you construct your data array.
xaroula mav
le 15 Avr 2015
xaroula mav
le 14 Avr 2015
0 votes
pfb
le 14 Avr 2015
What do you exactly mean by "this variable which is depicted above" and where would the \n be?
I think tdd4c1 answered to your question about the newline above. Doesn't it work?
As to converting a string to char, I think it's enough to enclose it in braces
cell_a = {a}
2 commentaires
xaroula mav
le 15 Avr 2015
Modifié(e) : xaroula mav
le 15 Avr 2015
oh, ok... maybe attaching the mat file containing the char variable instead of its graphical representation would be more helpful in pinpointing the problem.
Even better would be a small portion of the variable that sufficient to exemplify the problem (a minimal example, that is).
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