delete the top and bottom triangular faces of the 3D object

10 vues (au cours des 30 derniers jours)
Alberto Acri
Alberto Acri le 5 Oct 2023
Commenté : Alberto Acri le 9 Oct 2023
Hi! Is there a way to delete the top and bottom triangular faces of the tube?
nodes = importdata("NODES.mat");
faces = importdata("FACES.mat");
figure
plot3(nodes(:,1),nodes(:,2),nodes(:,3),'k.','Markersize',2);
hold on
trimesh(faces(:,:),nodes(:,1),nodes(:,2),nodes(:,3),'EdgeColor','k','Linewidth',0.1,'Facecolor','b','FaceAlpha',1)
hold off
axis equal

Réponse acceptée

Fabio Freschi
Fabio Freschi le 5 Oct 2023
By looking at your data I see that the top and bottom triangles have a predominant z direction of the face normals. So I play with this
% your code
nodes = importdata("NODES.mat");
faces = importdata("FACES.mat");
figure
plot3(nodes(:,1),nodes(:,2),nodes(:,3),'k.','Markersize',2);
hold on
trimesh(faces(:,:),nodes(:,1),nodes(:,2),nodes(:,3),'EdgeColor','k','Linewidth',0.1,'Facecolor','b','FaceAlpha',1)
hold off
axis equal
% create triangulation object to easily calculate face normals
TR = triangulation(faces,nodes);
P = incenter(TR);
F = faceNormal(TR);
% plot on the previous plot to see what's happening
hold on
quiver3(P(:,1),P(:,2),P(:,3), ...
F(:,1),F(:,2),F(:,3),0.5,'color','r');
% dot product with z directed unit vector
proj = F*[0 0 1].';
% threshold (play with this value)
idx = abs(proj) > 0.6;
% remove faces
faces(idx,:) = [];
% new plot without faces
figure
trimesh(faces(:,:),nodes(:,1),nodes(:,2),nodes(:,3),'EdgeColor','k','Linewidth',0.1,'Facecolor','b','FaceAlpha',1)
Hope it helps
  13 commentaires
Fabio Freschi
Fabio Freschi le 9 Oct 2023
% find normals oriented like u1 (dot product)
idx1 = abs(F*u1.') > 0.9999;
% find normals oriented like u2 (dot product)
idx2 = abs(F*u2.') > 0.9999;
% find barycenters laying on the magenta plane
ipln1 = abs(sum(P.*u1,2)-sum(u1.*P1,2)) < 0.001;
% find barycenters laying on the magenta plane
ipln2 = abs(sum(P.*u2,2)-sum(u2.*P2,2)) < 0.001;
% remove bottom lid
faces((idx1 & ipln1) | (idx2 & ipln2),:) = [];
Alberto Acri
Alberto Acri le 9 Oct 2023
Thank you!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Spatial Search dans Help Center et File Exchange

Produits


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by