How this code will look like for matlab?

% Initialization
delx = 1000 
delt = 5 
n = 211 
x = np.arange(0,n*delx,delx) 
h = np.zeros(n)
h[:int(l2/delx-1)] = h2
for i in range(int(l1/delx-1),int((l1+l3)/delx)): 
  h[i] = h2+(h1-h2)/l3*delx*(i-int(l1/delx-1))
h[int((l2+l3)/delx):n] = h1
% Depth in channel
plt.plot(range(0,n),-h)
plt.xlabel('simulation node')
plt.ylabel('Depth, m')
plt.show()
% Initial data
t = 0. # time
kt = 0 # iteration counter
q = np.zeros(n) # flow (barotropic velocity*depth*channel width)
z = np.zeros(n-1) # Level
# setting the level at the initial time
for i in range (int(n-1-l/delx-1),n-1):
   z[i] = a*np.cos(2*np.pi/2/l*(x[i]-x[int(n-1-l/delx)-1])-np.pi/2)
qold = q
zold = z
# Level at the initial time
plt.plot(range(0,n-1),z)
plt.plot(range(0,n),q)
plt.xlabel('simulation node')
plt.ylabel('Elevation, m')
plt.title('t = 0')
plt.show()
 
while t<t_stop : # time loop
   q[0] = 0. # boundary condition on the left solid boundary (impenetrability)
   for i in range(1,n-1): # cycle for calculating flows (speed) by channel length
     q[i] = qold[i] - delt*g*b*h[i]*(zold[i]-zold[i-1])/delx
   q[n-1] = b*zold[n-2]*np.sqrt(g*h[n-2]) # boundary condition on the right liquid boundary (radiation)
   for i in range(0,n-1): # cycle for calculating the level based on the channel length
     z[i] = zold[i] - delt/b*(q[i+1]-qold[i])/delx
  
   t = t + delt
   kt+= 1
   qold = q # override new thread array (speed)
   zold = z # override new level array
     #output
   if kt % 20 == 0: # frequency of results output
     print('t = ', t/60, 'min')
     fig, axs = plt.subplots(2,1,gridspec_kw={'height_ratios': [2, 1]})
     axs[0].plot(x[:-1]/1000,z)
     axs[0].set_ylabel('Elevation, m')
     axs[1].plot(x/1000,-h)
     axs[1].set_xlabel('Distance, km')
     axs[1].set_ylabel('Depth, m')
     plt.show()

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[Sulaymon Eshkabilov]

You can convert a Python code into MATLAB code using 3rd party applications like this one