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how can a symbolic derivative be vectorized automatically?

2 vues (au cours des 30 derniers jours)
Marko
Marko le 20 Oct 2023
Hello,
here is the simplified problem.
I have a symblic function with three arguments. And the derivative of f wrt. b
syms a b c
f = a*sin(b)*exp(c)
df = diff(f,b)
The solution is:
df = a*exp(c)*cos(b)
Now i will use this derivatve in a numeric script. And the argumetns a,b,c are vectors:
a=rand(10,1);
b=rand(10,1);
c=rand(10,1);
My current approach is to modify the derivative manualy: (adding "dots")
df = a.*exp(c).*cos(b)
Is there a way how i can change a symblic expression automatically?
My equations are has 80 or more characters and the derivatives has 2x to 3x the amount of characters.
So an automatic transform into an vectorized version would help me a lot.
Best regards,
MJ

Réponse acceptée

Stephen23
Stephen23 le 20 Oct 2023
Use MATLABFUNCTION:
syms a b c
f = a*sin(b)*exp(c)
f = 
df = diff(f,b)
df = 
mf = matlabFunction(df)
mf = function_handle with value:
@(a,b,c)a.*exp(c).*cos(b)
a=rand(10,1);
b=rand(10,1);
c=rand(10,1);
mf(a,b,c)
ans = 10×1
0.8287 0.4912 0.5251 2.2295 1.7548 0.0752 1.3973 0.6642 0.1812 0.5342

Plus de réponses (2)

Dyuman Joshi
Dyuman Joshi le 20 Oct 2023
Convert it to a function handle -
syms a b c
f = a*sin(b)*exp(c)
f = 
df = diff(f,b)
df = 
%Convert the symbolic function to an anonymous function
fun = matlabFunction(df)
fun = function_handle with value:
@(a,b,c)a.*exp(c).*cos(b)
a=rand(10,1);
b=rand(10,1);
c=rand(10,1);
fun(a,b,c)
ans = 10×1
1.6337 0.7283 1.9453 1.1977 0.0795 1.0797 0.8060 0.3090 2.5127 0.9578

Walter Roberson
Walter Roberson le 20 Oct 2023
format long g
syms a b c
f(a,b,c) = a*sin(b)*exp(c)
f(a, b, c) = 
df = diff(f,b)
df(a, b, c) = 
A = rand(10,1);
B = rand(10,1);
C = rand(10,1);
D = df(A, B, C)
D = 
vpa(D)
ans = 
double(D)
ans = 10×1
0.472553502790635 1.26659066678776 0.609162623765823 0.642273629496948 0.893411797110293 0.88743081840584 0.39637226337217 0.303468357868928 0.198740877661276 1.09526181869221

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