Effacer les filtres
Effacer les filtres

Help finding cell array indices for unique characters in string names

2 vues (au cours des 30 derniers jours)
How might i search a cell array for indices corresponding to character strings containing, say, 'H2O' as part of the full name. Tried:
exact_match_mask = strcmp(names, 'H2O'); exact_match_locations = find(exact_match_mask);
but it only identifies index 4. I need to identify the abcH2Oxyz possibility to capture indices 4 and 10.
names = cell(1, 10);
names{1} = '*H';
names{2} = 'HO2';
names{3} = '*H2';
names{4} = 'H2O';
names{5} = 'H2O2';
names{6} = '*O';
names{7} = '*OH';
names{8} = '*O2';
names{9} = 'O3';
names{10} = 'H2O(S)';
  4 commentaires
Voss
Voss le 20 Oct 2023
A more direct way of creating the cell array names is:
names = {'*H','HO2','*H2','H2O','H2O2','*O','*OH','*O2','O3','H2O(S)'};
Brantosaurus
Brantosaurus le 20 Oct 2023
cheers for that :)

Connectez-vous pour commenter.

Réponse acceptée

Sulaymon Eshkabilov
Sulaymon Eshkabilov le 20 Oct 2023
All combined into one:
names = cell(1, 10);
names{1} = '*H';
names{2} = 'HO2';
names{3} = '*H2';
names{4} = 'H2O';
names{5} = 'H2O2';
names{6} = '*O';
names{7} = '*OH';
names{8} = '*O2';
names{9} = 'O3';
names{10} = 'H2O(S)';
[TF, IDX] = find(contains(names,"H2O"))
TF = 1×3
1 1 1
IDX = 1×3
4 5 10
  1 commentaire
Brantosaurus
Brantosaurus le 20 Oct 2023
Fantastic. Many thanks for this.
The other contributions are also much appreciated :)

Connectez-vous pour commenter.

Plus de réponses (1)

the cyclist
the cyclist le 20 Oct 2023
names = cell(1, 10);
names{1} = '*H';
names{2} = 'HO2';
names{3} = '*H2';
names{4} = 'H2O';
names{5} = 'H2O2';
names{6} = '*O';
names{7} = '*OH';
names{8} = '*O2';
names{9} = 'O3';
names{10} = 'H2O(S)';
contains(names,'H2O')
ans = 1×10 logical array
0 0 0 1 1 0 0 0 0 1

Catégories

En savoir plus sur Characters and Strings dans Help Center et File Exchange

Produits


Version

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by