Ich erhalte
eqn(x) = y(x) == 0 | y(x)*diff(y(x), x, x) + diff(y(x), x)^2 == 0
Wie kann ich auf zweite Bedingung zugreifen?

3 commentaires

Dyuman Joshi
Dyuman Joshi le 8 Nov 2023
How do you get this particular expression?
Artur Walter
Artur Walter le 10 Nov 2023
I typed
f = y(x)^2 * (diff(y(x), x))^2
eqn = functionalDerivative(f,y) == 0
Dyuman Joshi
Dyuman Joshi le 22 Nov 2023
@Artur Walter, see my answer below.

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Réponses (2)

Dyuman Joshi
Dyuman Joshi le 16 Nov 2023

1 vote

syms y(x)
f = y(x)^2 * (diff(y(x), x))^2;
eqn = functionalDerivative(f,y) == 0;
%Get the equation mentioned in the question description by using simplify()
eqn = simplify(eqn)
eqn(x) = 
%Children of the expression
z = children(eqn)
z = 1×2 cell array
{[y(x) == 0]} {[y(x)*diff(y(x), x, x) + diff(y(x), x)^2 == 0]}
%Access the second condition
condition2 = z{2}
condition2 = 
Aiswarya
Aiswarya le 16 Nov 2023

0 votes

Hallo, ich würde die Frage auf Englisch beantworten.
(Hi,
I would be answering the question in English)
I understand that on equating a differential expression to zero, you obtained a conditional expression as a result.
The result obtained from the 'functionalDerviative' is a symbolic function and there is no direct way to just extract the second part of the "or" expression. However you can access the second condition by assuming condition for 'y' as shown in the following image.
You can use the assume function (https://www.mathworks.com/help/symbolic/sym.assume.html) to set non zero condition for y. And then simplify the equation to obtain just the second condition.

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