Illegal use of reserved keyword "elseif" keep showing up?

16 vues (au cours des 30 derniers jours)
mohammad
mohammad le 9 Nov 2023
Commenté : mohammad le 9 Nov 2023
function isortvector
A = [9 -7 8 4 -3 7]
inp = input("enter 0 for ascendig && 1 for decending");
ascending = [];
descendig = [];
if inp == '0'
for i = 1:6
x = A(1);
for j=1:length(A)
if A(j) < x
x=A(j);
end
end
ascending(end+1)=x; A(A==x)=[];
end
disp("Ascending:"); disp(ascending)
end
elseif inp =='1'
for i = 1:6
x=A(1);
for j=1:length(A)
if A(j) > x
x = A(j);
end
descending(end+1) = x; A(A==x)=[];
end
disp("Descending:");
disp(descendig)
disp("uncorect input:")
disp(A)
end
end
[SL: formatted code as code]
  1 commentaire
Stephen23
Stephen23 le 9 Nov 2023
Modifié(e) : Stephen23 le 9 Nov 2023
Note that as you have called it INPUT will return numeric values. If you expect characters (as you show use with IF and ELSEIF) then you will need to use the 's' option:
inp = input("enter 0 for ascendig && 1 for decending","s");
% ^^^
You also have to fix the names of some variables.

Connectez-vous pour commenter.

Réponse acceptée

Stephen23
Stephen23 le 9 Nov 2023
Modifié(e) : Stephen23 le 9 Nov 2023
If you align your code consistently then the problem is very clear:
if inp == '0'
..
end % <- delete this
elseif inp =='1'
..
end
Tip: to align code automatically select all of your code and press ctrl+i.

Plus de réponses (0)

Catégories

En savoir plus sur Data Type Conversion dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by