Effacer les filtres
Effacer les filtres

i have made a code which finds a specific value 'no' from the excel sheet but it does the job one by one. i want to automate it so it gives all values with 'no' at once.

1 vue (au cours des 30 derniers jours)
this is the code i'm using.
data = readtable('FINALconvergencecheck_ksst.xlsx');
data.Properties.VariableNames(1) = "an6cd";
data.Properties.VariableNames(3) = "an6cl";
data.Properties.VariableNames(5) = "an6cm";
data.Properties.VariableNames(7) = "ap0cd";
data.Properties.VariableNames(9) = "ap0cl";
data.Properties.VariableNames(11) = "ap0cm";
data.Properties.VariableNames(13) = "ap3cd";
data.Properties.VariableNames(15) = "ap3cl";
data.Properties.VariableNames(17) = "ap3cm";
data.Properties.VariableNames(19) = "ap7cd";
data.Properties.VariableNames(21) = "ap7cl";
data.Properties.VariableNames(23) = "ap7cm";
data.Properties.VariableNames(25) = "ap10cd";
data.Properties.VariableNames(27) = "ap10cl";
data.Properties.VariableNames(29) = "ap10cm";
data.Properties.VariableNames(31) = "ap12cd";
data.Properties.VariableNames(33) = "ap12cl";
data.Properties.VariableNames(35) = "ap12cm";
data.Properties.VariableNames(37) = "ap14cd";
data.Properties.VariableNames(39) = "ap14cl";
data.Properties.VariableNames(41) = "ap14cm";
data.Properties.VariableNames(43) = "ap15cd";
data.Properties.VariableNames(45) = "ap15cl";
data.Properties.VariableNames(47) = "ap15cm";
data.Properties.VariableNames(49) = "ap17cd";
data.Properties.VariableNames(51) = "ap17cl";
data.Properties.VariableNames(53) = "ap17cm";
data.Properties.VariableNames(2) = "an6cd_r";
data.Properties.VariableNames(4) = "an6cl_r";
data.Properties.VariableNames(6) = "an6cm_r";
data.Properties.VariableNames(8) = "ap0cd_r";
data.Properties.VariableNames(10) = "ap0cl_r";
data.Properties.VariableNames(12) = "ap0cm_r";
data.Properties.VariableNames(14) = "ap3cd_r";
data.Properties.VariableNames(16) = "ap3cl_r";
data.Properties.VariableNames(18) = "ap3cm_r";
data.Properties.VariableNames(20) = "ap7cd_r";
data.Properties.VariableNames(22) = "ap7cl_r";
data.Properties.VariableNames(24) = "ap7cm_r";
data.Properties.VariableNames(26) = "ap10cd_r";
data.Properties.VariableNames(28) = "ap10cl_r";
data.Properties.VariableNames(30) = "ap10cm_r";
data.Properties.VariableNames(32) = "ap12cd_r";
data.Properties.VariableNames(34) = "ap12cl_r";
data.Properties.VariableNames(36) = "ap12cm_r";
data.Properties.VariableNames(38) = "ap14cd_r";
data.Properties.VariableNames(40) = "ap14cl_r";
data.Properties.VariableNames(42) = "ap14cm_r";
data.Properties.VariableNames(44) = "ap15cd_r";
data.Properties.VariableNames(46) = "ap15cl_r";
data.Properties.VariableNames(48) = "ap15cm_r";
data.Properties.VariableNames(50) = "ap17cd_r";
data.Properties.VariableNames(52) = "ap17cl_r";
data.Properties.VariableNames(54) = "ap17cm_r";
display = find(data.ap10cl_r=="no");
k=display;
k1=string(k);
switch k1
case "yes"
disp('convereged')
case "no"
disp('not convereged')
end
here, i have to change the coulum again and again. i want to automate it in a way that it gives all the values where 'no' is at once.
kindly help.

Réponses (1)

Walter Roberson
Walter Roberson le 17 Nov 2023
display = find(data.ap10cl_r=="no");
The output in display will be a column vector of numeric row indices.
string() of that would be a string() array with the indices converted to displayable characters, such as
15
23
converted into
"15"
"23"
switch on these values will never match "yes" or "no"
Are you trying to display a list of row numbers that did not converge, and a list of row numbers that did converge? Did you want a column of output that has one entry per row and is more or less just an expansion of the current "no" and 'yes' entries to be more verbose?
  3 commentaires
Aditi
Aditi le 17 Nov 2023
I would like make a loop to find the ‘no’ values
VBBV
VBBV le 2 Juin 2024
Modifié(e) : VBBV le 2 Juin 2024
Val = data.ap10cl_r(display)

You can use the indices vector to find out all the values corresponding to "no" as above.

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