How do I add values to a vector? I have the vector gdl_off = [1,2,14] and the vector X with 11 positions. I want the values in the positions specified by gdl_off to be 0, but if I use X(gdl_off,:) = 0, it only replaces the existing values.
gld_off = [1,2,14];
X = Kg_cut\F_cut;
X(gdl_off,:) = 0
but i have this
0
0
0.000248324742039762
-0.000614863156129983
0.000173205080756888
-0.000715692193816531
0.000207846096908266
-0.000735692193816530
9.80854194740139e-05
-0.000614863156129983
0.000346410161513776
0
0
0
and my original X is
0.000138564064605510
-0.000735692193816531
0.000248324742039762
-0.000614863156129983
0.000173205080756888
-0.000715692193816531
0.000207846096908266
-0.000735692193816530
9.80854194740139e-05
-0.000614863156129983
0.000346410161513776

1 commentaire

if you only want it to replace values, but NOT add new elements to the vector if you specify assignment to non-existing entries, then limit the assignment indices to the current length of the vector:
x( intersect(gld_off,1:numel(x)) ,:) = 0
otherwise, i'm not sure what you're after or what you're expecting.

Connectez-vous pour commenter.

 Réponse acceptée

Voss
Voss le 12 Déc 2023
If you want to insert a zero element at each of the locations specified by gld_off, in turn, you can do this:
X = [0.000138564064605510;-0.000735692193816531;0.000248324742039762;-0.000614863156129983;0.000173205080756888;-0.000715692193816531;0.000207846096908266;-0.000735692193816530;9.80854194740139e-05;-0.000614863156129983;0.000346410161513776];
gld_off = [1,2,14];
for ii = 1:numel(gld_off)
X = [X(1:gld_off(ii)-1); 0; X(gld_off(ii):end)];
end
disp(X)
1.0e-03 * 0 0 0.1386 -0.7357 0.2483 -0.6149 0.1732 -0.7157 0.2078 -0.7357 0.0981 -0.6149 0.3464 0
However, the following is more efficient when you need to insert a large number of elements:
X = [0.000138564064605510;-0.000735692193816531;0.000248324742039762;-0.000614863156129983;0.000173205080756888;-0.000715692193816531;0.000207846096908266;-0.000735692193816530;9.80854194740139e-05;-0.000614863156129983;0.000346410161513776];
gld_off = [1,2,14];
NX_new = numel(X)+numel(gld_off);
X_new = zeros(NX_new,1);
X_new(setdiff(1:NX_new,gld_off)) = X;
X = X_new;
disp(X)
1.0e-03 * 0 0 0.1386 -0.7357 0.2483 -0.6149 0.1732 -0.7157 0.2078 -0.7357 0.0981 -0.6149 0.3464 0

2 commentaires

Gabriel Aguirre
Gabriel Aguirre le 12 Déc 2023
it worked, thank you
Voss
Voss le 12 Déc 2023
You're welcome!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

Produits

Version

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by