How we can do the matrix and vector in vector form?

clc;
clear all ;
 close all;
 format long g;

 %% developing the function for the reverse in the vector concate and reverse it

 A = [1;2;3]
 B = [4 5 6;8 9 11]
[numRows,numCols] = size(B)
 %% new vector will be vector form 

 C = vertcat(A,[B])

[Dyuman Joshi]

It's not clear what the expected output is.

[Vims]

I need answer in the vector form as it shown in image attached.

[Vims]

Answer 1

[madhan ravi]

 [A, B.'] %?

[madhan ravi]

 Wanted = [A; reshape(B.', [], 1)

[Vims]

I want function which also do the reverse. As the same format B was earlier. This is the another function. I think we have to use

[numRows,numCols] = size(B)

Answer 2

[madhan ravi]

 B = B.';
 Wanted = [A; B(:)]

[Vims]

correct but in reverse as same format or size. This is main part.

[numRows,numCols] = size(B)

Answer 3

[Dyuman Joshi]

I've demonstrated 2 methods here using reshape and colon, : . Refer to the documentation pages linked for more info.

Note that using semi-colon to concatenate is equivalent to vertcat.

A = [1;2;3];
B = [4 5 6;8 9 11];
%Method 1
C1 = [A; reshape(B.',[],1)]

C1 = 9×1

1 2 3 4 5 6 8 9 11

%Method 2
B = B.';
C2 = [A; B(:)]

C2 = 9×1

1 2 3 4 5 6 8 9 11

[Vims]

I need reverse function too as it should be go same size and format. This is biggest issue for any size and shape of matrix.

[Vims]

I think we have to use something like

[numRows,numCols] = size(B)

[Dyuman Joshi]

That's a good start.

Now, use indexing to split the data, and reverse the steps of method 1.