How to interpolate 2D array from 3D array?

A=[3 4 5 6 7];

numel(X)=23;

numel(Y)=42;

There are 5 different contour data with respect to X and Y like the one belove. I have 5 different contour data of 23x42, together a 3D array of 5x23x42. There are data for the given values of A, but l need data for interpolated values of A, for example in the case of A=4.7. Then l'll plot the data corresponding to the calculated value of A.

Thanks for your help!

[Mohammed]

A = [3 4 5 6 7]; X and Y coordinate arrays that contain: numel(X) = 23 (so 23 X values) numel(Y) = 42 (so 42 Y values)

You have 5 different contour datasets that are 23x42 matrices, corresponding to the different X and Y coordinate values. So altogether you have a 3D array of size 5x23x42 containing this contour data.

Your current data is at the values of A given in your array, such as A=3, A=4, A=5, etc.

But what you want is to interpolate to calculate the contour data at intermediate A values like A=4.7.

So the process would be:

1. Interpolate the 5x23x42 contour data to calculate an estimated contour dataset at A=4.7
2. Plot the interpolated contour data corresponding to A=4.7 along with the X and Y coordinate data.

[piston_pim_offset]

Which AI bot is this?

[Torsten]

@limon cu

I don't completely understand your question.

You have contour data on an x/y/z grid of size 5x23x42 and you have a value in between the 5 x-coordinates and you want to interpolate your 5x23x42 contour data to this value to get back a 23x42 matrix ?

[piston_pim_offset]

Yes, exactly. I have and contour plot of 23x42, and there are 5 of them wrt. 5 different values. I want to get interpolated interpolated data for every possible value of X.

Answer 1

[piston_pim_offset]

AI Chat Playground gave me this answer with an error:

contourData = randn(5, 23, 42);
A = [3 4 5 6 7];
interpContourData = interp1(A, contourData, 4.7);
[X, Y] = meshgrid(1:size(interpContourData, 2), 1:size(interpContourData, 3));
contourf(X, Y, squeeze(interpContourData), 20);

Error using contourf
The size of X must match the size of Z or the number of columns of Z.

Answer 2

[Dyuman Joshi]

Try this. Though I have no idea if it does what you asked for or not.

contourData = randn(5, 23, 42);
A = [3 4 5 6 7];
interpContourData = interp1(A, contourData, 4.7);

[X, Y] = meshgrid(1:size(interpContourData, 2), 1:size(interpContourData, 3));
interpContourData = permute(interpContourData, [3 2 1]);

contourf(X, Y, squeeze(interpContourData), 20)

[piston_pim_offset]

Much thanks, it worked.

Answer 3

[Torsten]

contourData = randn(5, 23, 42);
x = 1:5;
y = 1:23;
z = 1:42;
X = [2.6 4.7];
contourData_interpolated = zeros(numel(X),23,42);

for j = 1:23
    for k = 1:42
        contourData_interpolated(:,j,k) = interp1(x,squeeze(contourData(:,j,k)),X);
    end
end