Adding anonymous functions stored in a cell

I have a cell of functions, which I want to add after integration of each in the cell. Further, I have to multply each fucntion with a constant from another cell. This new cells of anonymous functions thus obtained is to be added .i.e the elements have to be summed up. I tried using a for loop. Following is a approach I used,but I do not seem to be getting the right constant i.e. in the function MATLAB just shows cons{j} instead of the actual value stored there (a symbolic constant). Neither am I getting the summed up total funtion. Kindly help.

f = {@(x)x , @(x)x^2}

syms a b

c = {a b}

g = @(y) y

h = 0;

for j=1:length(2)

h = @(x) c{j}*integral(f{j}(x), 0,1) + h

end

Answer 1

[Dyuman Joshi]

Use symbolic integration -

syms x a b
f =  {x x^2}

f = 1×2 cell array
    {[x]}    {[x^2]}

c = [a b];

h = 0;
for j=1:numel(f)
    h = c(j)*int(f{j}, x, 0, 1) + h;
end

h

h = 

[Aviral Srivastava]

Turns out I can not use symbolic variable to carry out my integration. You might remember it from my previous querry on Multivariable Integration. Is there any way I can do this in an interative method?

[Dyuman Joshi]

I see.

Try this -

f =  @(x) [x x.^2]

f = function_handle with value:
    @(x)[x,x.^2]

out = integral(f, 0, 1, 'ArrayValued', 1)

out = 1×2

0.5000 0.3333

syms a b
c = [a b];

h = c.*out

h = 

[Aviral Srivastava]

Sorry, this doesn't seem to be working for me: -

f = @(x) [x , x.^2]

syms a b

c = [a b]

g = @(y) y

h = @(x,y) f(x).*g(y)

out = @(y) integral(@(x) h(x,y), 0,1,true)

out = @(y) c.*out(y)

out(5)

[Dyuman Joshi]

'ArrayValued' is missing from the integral() call -

f = @(x) [x , x.^2];
syms a b
c = [a b];
g = @(y) y;
h = @(x,y) f(x).*g(y);
fun = @(y) c.*integral(@(x) h(x,y), 0,1, 'ArrayValued', 1)

fun = function_handle with value:
    @(y)c.*integral(@(x)h(x,y),0,1,'ArrayValued',1)

out = fun(5)

out = 

[Aviral Srivastava]

Thank you!

[Dyuman Joshi]

You're welcome!