Effacer les filtres
Effacer les filtres

How to get the value of slopes of pchip at the enpoints?

3 vues (au cours des 30 derniers jours)
David Gillcrist
David Gillcrist le 7 Jan 2024
I'm using pchip to interpolate a set of data X. After getting the interpolation, I'm trying to have functions g and f, connect to the endpoints of the interpolation. I want g and f to have the same slopes where they connect to the endpoints. Is there a convenient way to get the values of the slopes of the pchip interpolation?

Réponse acceptée

Paul
Paul le 7 Jan 2024
The doc page pchip (under the Output Arguments, pp section) shows how the interpolationg polynominal is formed for each interval based on the breakpoints and the pp coefficients, from which it should be straighforward to compute the derivative at the leading and trailing edges of the first and last intervals respectively.
x = 0:.1:1;y=sin(x);
pp = pchip(x,y);
pp
pp = struct with fields:
form: 'pp' breaks: [0 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1] coefs: [10×4 double] pieces: 10 order: 4 dim: 1
Not sure why pp.oder = 4. That seems odd for a cubic polynomial.
  1 commentaire
David Gillcrist
David Gillcrist le 8 Jan 2024
It looks like it counts the constant coefficient as a dimension. I should be able to use this to get the slope values there.

Connectez-vous pour commenter.

Plus de réponses (1)

Matt J
Matt J le 7 Jan 2024
Modifié(e) : Matt J le 7 Jan 2024
You don't need to determine the end slopes to extrapolate X. Just use the 'extrap' option to obtain values where desired outside the boundaries of X.
You could also do a finite-difference approximation, e.g.,
x=sort(rand(1,10)); y=rand(size(x)); f=@(z) interp1(x,y,z,'pchip','extrap');
ye=y(end); delta=eps(ye);
endslope = ( f(ye+delta) - f(ye) )/delta
endslope = 24

Catégories

En savoir plus sur Interpolation dans Help Center et File Exchange

Produits


Version

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by