I have been working on 50 non linear differential equation with fsolve but it always give me this answer please help how can i solve this problem

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I have been working on fins equation and faced non linear eqaution so i have used fsolve command but every time it show this thing
  5 commentaires
Torsten
Torsten le 13 Jan 2024
Modifié(e) : Torsten le 13 Jan 2024
I have apply fdm central scheme so d.e changes in ko 50 non linear algebraic eqaution
But in the title you write that you work on 50 nonlinear differential equations ...
Maybe using a solver for boundary value problems is a better choice than discretizing on your own. Look up "bvp4c" or "bvp5c".

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Sulaymon Eshkabilov
Sulaymon Eshkabilov le 14 Jan 2024
There are a couple of points to consider.
(1) if fsolve() has to be used, then fsolve()'s options need to be set up to perform N number of iterations, e.g.:
% Function handle of the problem to be solved solve
EQNs = @(x) ([x(1)^2 + x(2)^2 - 1;
exp(x(1)) + x(2) - 2;
sin(x(1) + x(2)) - x(3);
cos(x(4)) - x(5)^2;
log(x(4) + x(5)) - 3]);
% Number of Iterations to perform:
N = 10;
% Set the options of fsolve():
OPTs = optimoptions('fsolve', 'MaxIter', N, 'Display','iter');
% Initial Guess Solutions:
X_guess = [1; 1; 1; 1; 1];
% Solve the system of equations
[Solution, Fval] = fsolve(EQNs, X_guess, OPTs)
Norm of First-order Trust-region Iteration Func-count ||f(x)||^2 step optimality radius 0 6 9.49361 6.71 1 1 12 5.13647 1 0.859 1 2 13 5.13647 2.5 0.859 2.5 3 19 4.89156 0.625 0.304 0.625 4 20 4.89156 0.625 0.304 0.625 5 26 4.80326 0.15625 0.196 0.156 6 32 4.73656 0.15625 0.176 0.156 7 38 4.67347 0.390625 0.339 0.391 8 39 4.67347 0.390625 0.339 0.391 9 45 4.59588 0.0976562 0.278 0.0977 10 51 4.46835 0.244141 0.36 0.244 Solver stopped prematurely. fsolve stopped because it exceeded the iteration limit, options.MaxIterations = 1.000000e+01.
Solution = 5×1
0.0865 0.9929 0.8962 2.9799 0.3517
Fval = 5×1
-0.0066 0.0833 -0.0145 -1.1107 -1.7966
disp('Found solution: ')
Found solution:
disp(Solution)
0.0865 0.9929 0.8962 2.9799 0.3517
(2) lsqnonlin() is good to solve large size nonlinear problems:
% Function handle of the problem to be solved solve
EQNs = @(x) ([x(1)^2 + x(2)^2 - 1;
exp(x(1)) + x(2) - 2;
sin(x(1) + x(2)) - x(3);
cos(x(4)) - x(5)^2;
log(x(4) + x(5)) - 3]);
% Initial Guess Solutions:
X_guess = [1; 1; 1; 1; 1];
% Set Lower bound:
LB = [0; 0; 0; 0; 0; ];
% Set Lower bound:
UB = [10; 10; 10; 10; 10; ];
% Max Number of Iterations:
N = 10;
% Options set up:
OPT2 = optimoptions('lsqnonlin', 'MaxIterations', N, 'Display','iter');
% Use lsqnonlin() to solve EQNs:
[SOLUTION, FVAL] = lsqnonlin(EQNs, X_guess, LB, UB, OPT2)
Norm of First-order Iteration Func-count Resnorm step optimality 0 6 9.49361 6.9 1 12 6.03506 0.815721 4.66 2 18 4.72506 1.09483 9.26 3 24 2.02104 0.273708 2.82 4 30 1.36831 0.547416 1.89 5 36 0.931038 0.424434 0.582 6 42 0.894717 0.499556 2.09 7 48 0.819859 0.124889 0.0684 8 54 0.819032 0.249778 0.238 9 60 0.816667 0.0624444 0.247 10 66 0.814251 0.0624444 0.00533 11 72 0.812845 0.137778 0.0771 Solver stopped prematurely. lsqnonlin stopped because it exceeded the iteration limit, options.MaxIterations = 1.000000e+01.
SOLUTION = 5×1
0.0280 0.9944 0.8535 7.7640 0.4494
FVAL = 0.8128
  6 commentaires
Akasha
Akasha le 14 Jan 2024
Modifié(e) : Akasha le 14 Jan 2024
this is the output which matlab gives me i dont know how to solve it fully please help me

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