Second order ordinary differential equation
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I am trying to find the exact solution of this differential equation, but the error 'explicit solution not found' occur -y''(x) +2cos2x*y(x) -lambda*y(x) =0
3 commentaires
Dyuman Joshi
le 15 Jan 2024
Modifié(e) : Dyuman Joshi
le 15 Jan 2024
Please show the code that resulted in the "error" mentioned.
Abdul
le 15 Jan 2024
The notation is a bit ambiguous.
Note that it matters in the end.
syms y(x) lambda
dy = diff(y);
d2y = diff(dy);
eqn = d2y + 2 * cos(2*x) * y - lambda*y == 0
dsolve(eqn)
eqn2 = d2y + 2 * cos(2*x * y) - lambda*y == 0
dsolve(eqn2)
Réponses (1)
Sam Chak
le 15 Jan 2024
0 votes
Hi @Abdul
I believe that 'explicit solution not found' is more of a notification than an error message. Upon closer inspection, your second-order system appears to resemble the Mathieu Differential Equation. If that's the case, the solution is provided in the form of the Mathieu function. For additional information, please refer to the following file on File Exchange:
1 commentaire
@Abdul, I don't know how to express the Mathieu functions in MATLAB, but I simulated the Mathieu differential equation for different values of lambda (λ) to observe the stability of the solutions.
lambda = 1:6;
t = 0:0.01:60;
y0 = [1; 0];
for j = 1:numel(lambda)
sol = ode45(@(t, y) MathieuDE(t, y, lambda(j)), t, y0);
y = deval(sol, t);
subplot(2, 3, j)
plot(y(1,:), y(2,:)), grid on
xlabel('y_{1}'), ylabel('y_{2}')
title("\lambda = "+string(lambda(j)))
axis equal
end
%% Mathieu Differential Equation
function dydt = MathieuDE(t, y, lambda)
dydt = zeros(2, 1);
dydt(1) = y(2);
dydt(2) = 2*cos(2*t)*y(1) - lambda*y(1);
end
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