Simplifying for-find loop functions to speed up processing
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Hi all,
A pretty basic question, but I'm trying to find a more elegant solution to search through a 750,000x5 list to remove entries from a corresponding list when more than three value in any respective row are above a threshold of 10. The long way of doing so that I have is
% mD is a 750000 x 5 matrix containing distances to the nearest 5
% neighbors of the r,c,v point (from knnsearch) in each row
for i = size(r,1):-1:1
if size(find(mD(i,:)>10),2) > 3
r(i) = [];
c(i) = [];
v(i) = [];
end
end
4 commentaires
Torsten
le 26 Jan 2024
Are there more than 3 values in mD row (i) above 10?
But you don't refer to row i of mD in your loop - you refer to the complete matrix mD with your find-command.
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Dyuman Joshi
le 26 Jan 2024
Modifié(e) : Dyuman Joshi
le 26 Jan 2024
I assume r, c and v have the same number of rows -
%Check which rows from the given range in mD have more than 3 values greater than 10
idx = sum(mD(1:size(r,1),:)>10, 2)>3
%perform deletion
r(idx) = [];
c(idx) = [];
v(idx) = [];
If all the variables have the same number or rows then you can remove the indices used and just use mD.
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