how to split principal vector "a" into sub vectors a1, a2, a3 and a4
exemple:
a=[1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39];
a1=[1 3 5 8];
a2=[11 12 15 17 18 19 20];
a3=[21 24 29];
a4=[31 32 33 34 35 36 38 39];
thnkx

3 commentaires

Stephen23
Stephen23 le 30 Jan 2024
Modifié(e) : Stephen23 le 30 Jan 2024
What is the rule for splitting into those vectors?
For example:
  • why is 20 in a2 and not in a3 ?
  • why is 21 in a3 and not in a2 ?
Note that creating numbered variables is not a good approach. Much better to use a cell array.
benghenia aek
benghenia aek le 30 Jan 2024
I want to split the big array "a" into:
a1 "the numbers between 0 and 10"
a2 "the numbers between 11 and 20"
a3 "the numbers between 21 and 30"
and make it into cell arrays
Dyuman Joshi
Dyuman Joshi le 19 Fév 2024
Any updates, @benghenia aek?

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 Réponse acceptée

Dyuman Joshi
Dyuman Joshi le 30 Jan 2024
Modifié(e) : Dyuman Joshi le 19 Fév 2024
a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39 69].';
%bin the data into groups of 10
k = findgroups(floor((a-1)/10));
z = accumarray(k, a, [], @(x) {x.'})
z = 5×1 cell array
{[ 1 3 5 8]} {[ 11 12 15 17 18 19 20]} {[ 21 24 29]} {[31 32 33 34 35 36 38 39]} {[ 69]}

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Matt J
Matt J le 30 Jan 2024
Modifié(e) : Matt J le 19 Fév 2024
a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39];
G=findgroups(discretize(a,[0:10:max(a)+10],'Include','right'));
z=splitapply(@(x){x}, a, G)
z = 1x4 cell array
{[1 3 5 8]} {[11 12 15 17 18 19 20]} {[21 24 29]} {[31 32 33 34 35 36 38 39]}

2 commentaires

splitapply() won't work if there is a gap in the data -
a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39 69];
G=discretize(a,[0:10:max(a)+10],'Include','right');
z=splitapply(@(x){x}, a, G)
Error using splitapply
For N groups, every integer between 1 and N must occur at least once in the vector of group numbers.
Small modification,
a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39 69];
G=findgroups(discretize(a,[0:10:max(a)+10],'Include','right'));
z=splitapply(@(x){x}, a, G)
z = 1x5 cell array
{[1 3 5 8]} {[11 12 15 17 18 19 20]} {[21 24 29]} {[31 32 33 34 35 36 38 39]} {[69]}

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