How to solve complex equations?
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I am trying to solve the following equation.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1616073/image.png)
I have the following script to solve for theta, but getting erro when I am running the program.
Any suggestions is much appreciated.
Thank you.
clc;
clear;
close all;
syms theta
assume(0 <= theta <= 2*pi)
t = 0.4e-3;
n = 1.523;
delta_y = 3;
S1 = solve(delta_y == t*sind(theta)*(1 - sqrt((1-sind(theta)^2)/n^2 - sind(theta)^2)),theta);
3 commentaires
Réponse acceptée
Torsten
le 13 Fév 2024
Modifié(e) : Torsten
le 13 Fév 2024
Your equation has only complex solutions.
Note that you used sind instead of sin in the function definition. Thus assuming theta in radians is wrong.
clc;
clear;
close all;
syms theta
%assume(0 <= theta <= 2*pi)
t = 0.4e-3;
n = 1.523;
delta_y = 3;
S1 = solve(delta_y == t*sind(theta)*(1 - sqrt((1-sind(theta)^2)/(n^2 - sind(theta)^2))),theta,'ReturnConditions',1,'MaxDegree',3)
vpa(S1.theta)
S1.parameters
S1.conditions
5 commentaires
Torsten
le 14 Fév 2024
Modifié(e) : Torsten
le 14 Fév 2024
If you use the new parameters, you get back some real solutions:
clc;
clear;
close all;
syms theta
t = 0.7e-3;
n = 1.533;
delta_y = 21.2991*1e-6;
S1 = vpa(solve(delta_y == t*sind(theta)*(1 - sqrt((1-sind(theta)^2)/(n^2 - sind(theta)^2))),theta,'MaxDegree',3))
format long
S1 = double(S1(abs(imag(S1))<1e-6))
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Special Values dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!